我如何找到我在Django中遇到的500错误？ [英] How can I find out what 500 error am I getting in Django?
问题描述
当我访问由Django产生的服务器上提供的Django应用程序中的页面（http://68.123.151.234/static/quickstart.html）时，该页面读取
When I visit a page (http://68.123.151.234/static/quickstart.html) in my Django application served on a server spawned by Django, the page reads
A server error occurred. Please contact the administrator.
我收到这个追溯。
Traceback (most recent call last):
File "/usr/lib/python2.7/wsgiref/handlers.py", line 85, in run
self.result = application(self.environ, self.start_response)
File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/wsgi.py", line 241, in __call__
response = self.get_response(request)
File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 153, in get_response
response = self.handle_uncaught_exception(request, resolver, sys.exc_info())
File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 228, in handle_uncaught_exception
return callback(request, **param_dict)
File "/usr/local/lib/python2.7/dist-packages/django/utils/decorators.py", line 91, in _wrapped_view
response = view_func(request, *args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/django/views/defaults.py", line 32, in server_error
t = loader.get_template(template_name) # You need to create a 500.html template.
File "/usr/local/lib/python2.7/dist-packages/django/template/loader.py", line 145, in get_template
template, origin = find_template(template_name)
File "/usr/local/lib/python2.7/dist-packages/django/template/loader.py", line 138, in find_template
raise TemplateDoesNotExist(name)
TemplateDoesNotExist: 500.html
[17/May/2012 11:31:45] "GET /static/quickstart.html HTTP/1.1" 500 59
Traceback (most recent call last):
File "/usr/lib/python2.7/wsgiref/handlers.py", line 85, in run
self.result = application(self.environ, self.start_response)
File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/wsgi.py", line 241, in __call__
response = self.get_response(request)
File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 153, in get_response
response = self.handle_uncaught_exception(request, resolver, sys.exc_info())
File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 228, in handle_uncaught_exception
return callback(request, **param_dict)
File "/usr/local/lib/python2.7/dist-packages/django/utils/decorators.py", line 91, in _wrapped_view
response = view_func(request, *args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/django/views/defaults.py", line 32, in server_error
t = loader.get_template(template_name) # You need to create a 500.html template.
File "/usr/local/lib/python2.7/dist-packages/django/template/loader.py", line 145, in get_template
template, origin = find_template(template_name)
File "/usr/local/lib/python2.7/dist-packages/django/template/loader.py", line 138, in find_template
raise TemplateDoesNotExist(name)
TemplateDoesNotExist: 500.html
此追溯仅告诉我，我需要一个500模板 - 而不是实际的服务器错误。我如何找出服务器错误是什么？
This traceback only tells me that I need a 500 template - not what the actual server error is. How can I find out what the server error was?
我查看了Django文档（ https://docs.djangoproject.com/en/1.4/topics/http/views/ ），它指示我创建一个500错误模板作为潜在的解决方案。但是，它没有指示如何在这样的模板中显示错误。
I checked out Django documentation (https://docs.djangoproject.com/en/1.4/topics/http/views/), which directs me to create a 500 error template as a potential solution. However, it gives no instructions as to how to display the error within such a template.
推荐答案
基本的500.html是如Alasdair所说，方便有用，可能会揭示一些敏感的东西。
A basic 500.html which is convenient and useful would, as Alasdair said, potentially reveal something sensitive.
但是，如果以负责任的方式调试网络是目标，那么您的网站模板目录的基本nondefault500.html模板将看起来像
However, if debugging over the web in a responsible way is the objective, a basic nondefault500.html template for your site template dir would look like
<html><head><body>
<!-- starting with sys.exc_info but hey, it's python -->
Type: {{ type }} <br />
Value: {{ value }} <br />
Traceback: {{ traceback }} <br />
</body></head></html>
，新处理程序将填充该上下文：
and the new handler would populate that context as such:
def this_server_error(request, template_name='nondefault500.html'):
"""
500 error handler.
Templates: `500.html`
Context: sys.exc_info() results
"""
t = loader.get_template(template_name) # You need to create a 500.html template.
ltype,lvalue,ltraceback = sys.exc_info()
sys.exc_clear() #for fun, and to point out I only -think- this hasn't happened at
#this point in the process already
return http.HttpResponseServerError(t.render(Context({'type':ltype,'value':lvalue,'traceback':ltraceback})))
，需要进行一个URLconf调整，
and there would need to be a URLconf adjustment made,
handler500 = 'mysite.views.this_server_error'
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