如何知道一个bug生成的一个bug生成的bean？ [英] How to know the line of a bug in a spring generated bean?

问题描述

我有一个使用Spring和jpa（由hibernate）构建的网站。我有一个错误，我不知道如何识别错误出现的行。

我无法调试它，因为它是一个现实版本（全部在本地运行）。

我有日志说：
o

  rg.springframework.aop.framework.ReflectiveMethodInvocation.proceed（ReflectiveMethodInvocation.java:172）＃012＃011 
 
在org.springframework.aop.framework.Cglib2AopProxy $ DynamicAdvisedInterceptor.intercept（Cglib2AopProxy.java:625）＃012＃011 
 
 at com.mycompany.server.rpc.UserService $$ EnhancerByCGLIB $$ 64ed2d4f.createAccount（< generate>）＃012＃ 011 
 
 at com.mycompany.server.rpc.ServiceRPCImpl.createAccount（ServiceRPCImpl.java:309）
  

我的问题是第三行。由于UserService对象由Spring处理，它成为一个代理，我无法知道该错误的一行。

你知道如何解决问题吗？ / p>

谢谢

解决方案

是否可以将您从cglib更改为jdk代理？ （ Spring AOP代理参考）

基本上：如果您将bean作为接口访问，可以使用jdk代理（弹簧默认机制），从而使底层对象保持原样，并获得访问堆栈跟踪中的行号。

I've got a website build with Spring and jpa (by hibernate). I've got a bug and I don't know how to identify the line where the bug appears.

I can't debug it on my ide because it's a live version (all runs fine in local).

I've got log which says: o

rg.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:172)#012#011

at org.springframework.aop.framework.Cglib2AopProxy$DynamicAdvisedInterceptor.intercept(Cglib2AopProxy.java:625)#012#011

at com.mycompany.server.rpc.UserService$$EnhancerByCGLIB$$64ed2d4f.createAccount(<generated>)#012#011

at com.mycompany.server.rpc.ServiceRPCImpl.createAccount(ServiceRPCImpl.java:309)

My problem is the third line. As the UserService object is handled by Spring, it becomes a proxy and I can't know the line of the bug.

Do you know how to solve the problem ?

Thanks

解决方案

Is it possible for you to change from cglib to jdk proxy? (Spring AOP proxy reference)

Basically: if you access your beans as interfaces, you can use jdk proxies (spring default mechanism), thereby leaving the underlying object intact and gaining access to line numbers in stack traces.

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