为什么没有标准:: copy_if算法？ [英] Why there is no std::copy_if algorithm?

问题描述

有什么具体原因没有在C ++的std :: copy_if算法？我知道我可以使用std :: remove_copy_if达到所要求的行为。我认为这是未来在C ++ 0x中，但一个简单的copy_if这需要一个范围，一个输出迭代器和函数对象本来不错。当时它只是简单地错过了或者是有一些背后的其他原因？

Is there any specific reason for not having std::copy_if algorithm in C++ ? I know I can use std::remove_copy_if to achieve the required behavior. I think it is coming in C++0x, but a simple copy_if which takes a range, a output iterator and a functor would have been nice. Was it just simply missed out or is there some other reason behind it?

推荐答案

据Stroustrup的C ++程序设计语言，其实只是一种过度的视线。

According to Stroustrup's "The C++ Programming Language" it was just an over-sight.

（作为引证，同样的问题回答升压邮件列表： copy_if ）

(as a citation, the same question answered in boost mail-lists: copy_if)

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