C＃正态随机数 [英] C# Normal Random Number

问题描述

我想创建一个函数，接受双平均值，双偏差，并返回一个随机数与正态分布。

I would like to create a function that accepts Double mean, Double deviation and returns a random number with a normal distribution.

例如：如果我通过在5.00的平均值2.00作为偏差的时候68％，我会得到3.00和7.00之间的数字。

Example: if I pass in 5.00 as the mean and 2.00 as the deviation, 68% of the time I will get a number between 3.00 and 7.00

我的统计是有点弱...。任何人有一个想法，我应该如何处理呢？我的实现将是C＃2.0中，但随时只要数学函数是标准在您所选择的语言来回答。

My statistics is a little weak…. Anyone have an idea how I should approach this? My implementation will be C# 2.0 but feel free to answer in your language of choice as long as the math functions are standard.

我觉得<一个href="http://stackoverflow.com/questions/1197321/need-help-generating-discrete-random-numbers-from-distribution/1197393#1197393">this实际上可能是我所期待的。任何帮助转化这code？

I think this might actually be what I am looking for. Any help converting this to code?

在此先感谢您的帮助。

推荐答案

请参阅此$ C $的CProject文章：简单的随机数生成。在code是很短的，它产生的样本不统一，正常，指数分布。

See this CodeProject article: Simple Random Number Generation. The code is very short, and it generates samples from uniform, normal, and exponential distributions.

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