如何打印字典的关键字? [英] How to print a dictionary's key?
问题描述
mydic = {}
mydic ['key_name'] = 'value_name'
现在我可以检查 mydic.has_key('key_name' )
,但我想做的是打印密钥的名称'key_name'
。当然,我可以使用 mydic.items()
,但我不希望列出所有的键所有,只是一个特定的键。例如,我希望这样(伪代码):
打印密钥名称,mydic [ 'key_name']。name_the_key(),,其值为,mydic ['key_name']
是否有任何 name_the_key()
方法来打印密钥名称?
编辑:
好的,谢谢你们的反应! :)我意识到我的问题没有很好的表达和微不足道的。我感到困惑,因为我意识到key_name和 mydic ['key_name']
是两个不同的东西,我认为打印 key_name
出了字典上下文。但是我确实可以使用'key_name'来引用这个键! :)
根据定义,字典具有任意数量的键。没有关键。您有 keys()
方法,它为您提供了所有密钥的python 列表
,并且您具有 iteritems()
方法,它返回键值对,所以
for key,mydic.iteritems()中的值:
打印键,值
Python 3版本:
为密钥,mydic.items()中的值:
print(key,value)
所以你有一个关键字的句柄,但是如果耦合到一个值,它们只是真的意义上的意义。我希望我了解你的问题。
I found a my question in SO already, but it was not answered directly. I would like to print a specific Python dictionary key:
mydic = {}
mydic['key_name'] = 'value_name'
Now I can check if mydic.has_key('key_name')
, but what I would like to do is print the name of the key 'key_name'
. Of course I could use mydic.items()
, but I don't want all the keys listed, merely one specific key. For instance I'd expect something like this (in pseudo-code):
print "the key name is", mydic['key_name'].name_the_key(), "and its value is", mydic['key_name']
Is there any name_the_key()
method to print a key name?
Edit:
OK, thanks a lot guys for your reactions! :) I realise my question is not well formulated and trivial. I just got confused because i realised key_name and mydic['key_name']
are two different things and i thought it would incorrect to print the key_name
out of the dictionary context. But indeed i can simply use the 'key_name' to refer to the key! :)
A dictionary has, by definition, an arbitrary number of keys. There is no "the key". You have the keys()
method, which gives you a python list
of all the keys, and you have the iteritems()
method, which returns key-value pairs, so
for key, value in mydic.iteritems() :
print key, value
Python 3 version:
for key, value in mydic.items() :
print (key, value)
So you have a handle on the keys, but they only really mean sense if coupled to a value. I hope I have understood your question.
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