在Groovy中添加两个地图,同时总结公共密钥的值 [英] Add two maps in Groovy while summing up values for common keys
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问题描述
[a:1,b:2]
和 [b:1,c:3]
并希望从他们创建第三张地图 [a:1,b:3,c:3]
。有没有一个Groovy命令? 编辑:请注意,第三个地图中的值是前两个地图,如果密钥是相同的。
谢谢
解决方案
另一个解决方案是:
def m1 = [a:1,b:2]
def m2 = [b:1,c:3]
def newMap = [m1,m2] *。keySet()。flatten()。unique()。collectEntries {
[(it) [m1,m2] *。get(it).findAll()。sum()]
}
将流行病人的回答作为灵感,您还可以编写一个方法来处理多个地图
def m1 = [a:1,b:2]
def m2 = [b:1,c:3]
def combine(Map ... m){
m.collectMany {it.entrySet()} .inject([:]){result,e - >
结果<< [(e.key):e.value +(result [e.key]?:0)]
}
}
def newMap = combine(m1,m2)
I have two maps in Groovy [a: 1, b: 2]
and [b:1, c:3]
and would like to create from them a third map [a: 1, b: 3, c: 3]
. Is there a Groovy command that does that?
Edit: Notice that the values in the third map, are a sum of the values from the first two maps, if the keys are identical.
Thanks
解决方案
Yet another solution would be:
def m1 = [ a:1, b:2 ]
def m2 = [ b:1, c:3 ]
def newMap = [m1,m2]*.keySet().flatten().unique().collectEntries {
[ (it): [m1,m2]*.get( it ).findAll().sum() ]
}
Taking epidemian's answer as inspiriation, you can also write a method to handle multiple maps
def m1 = [a: 1, b: 2]
def m2 = [b: 1, c: 3]
def combine( Map... m ) {
m.collectMany { it.entrySet() }.inject( [:] ) { result, e ->
result << [ (e.key):e.value + ( result[ e.key ] ?: 0 ) ]
}
}
def newMap = combine( m1, m2 )
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