每当有一个密钥匹配时,添加两个地图的值 [英] Adding values of two maps whenever there is a key match
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问题描述
{one = 1; 2 = 1;三= 1}
另一个地图如
{一个= 4; 2 = 4;我知道putAll()会添加唯一的键并替换现有的键。
可以添加两个地图,这些地图会产生一个结果,比如在有现有的关键字时添加值。 {一个= 5; 2 = 5;三= 5}
解决方案扩展 HashMap 并覆盖putAll方法。
public class MyMap extends java.util.HashMap {
@Override
public void putAll(java.util.Map mapToAdd){
java.util.Iterator iterKeys = keySet()。iterator();
while(iterKeys.hasNext()){
String currentKey =(String)iterKeys.next();
if(mapToAdd.containsKey(currentKey)){
mapToAdd.put(currentKey,new Integer(Integer.parseInt(get(currentKey).toString())+ Integer.parseInt(mapToAdd.get(currentKey )的ToString())));
} else {
mapToAdd.put(currentKey,get(currentKey));
}
}
super.putAll(mapToAdd);
}
public static void main(String args []){
MyMap m1 = new MyMap();
m1.put(One,new Integer(1));
m1.put(Two,new Integer(2));
m1.put(Three,new Integer(3));
MyMap m2 = new MyMap();
m2.put(One,new Integer(4));
m2.put(Two,new Integer(5));
m2.put(Three,new Integer(6));
m1.putAll(m2);
System.out.println(m1);
}
}
现在,创建MyMap的对象而不是HashMap。创建小提琴此处
Say I have a map like
{one=1; two=1; three=1}
and another map like
{one=4; two=4; three=4}
I know that putAll() would add unique keys and replace existing keys.
Will it be possible to do an addition of both the maps which would produce a result like adding the values whenever there is an existing keyword.
{one=5; two=5; three=5}
解决方案 Extend the HashMap and override the putAll method.
public class MyMap extends java.util.HashMap{
@Override
public void putAll(java.util.Map mapToAdd){
java.util.Iterator iterKeys = keySet().iterator();
while(iterKeys.hasNext()){
String currentKey = (String)iterKeys.next();
if(mapToAdd.containsKey(currentKey)){
mapToAdd.put(currentKey, new Integer(Integer.parseInt(get(currentKey).toString()) + Integer.parseInt(mapToAdd.get(currentKey).toString())));
}else{
mapToAdd.put(currentKey, get(currentKey));
}
}
super.putAll(mapToAdd);
}
public static void main(String args[]){
MyMap m1 = new MyMap();
m1.put("One", new Integer(1));
m1.put("Two", new Integer(2));
m1.put("Three", new Integer(3));
MyMap m2 = new MyMap();
m2.put("One", new Integer(4));
m2.put("Two", new Integer(5));
m2.put("Three", new Integer(6));
m1.putAll(m2);
System.out.println(m1);
}
}
Now, create objects of MyMap instead of HashMap. Created a fiddle Here
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