按键长度排序字典 [英] sort dictionary by key length

问题描述

可能重复：

按密钥长度排序的字典

我需要使用字典用于搜索和替换。而我首先要使用最长的钥匙。

I need to use dictionary for "search and replace". And I want that first it use longest keys.

所以

text = 'xxxx'
dict = {'xxx' : '3','xx' : '2'} 
for key in dict:
    text = text.replace(key, dict[key])

应该返回3x，而不是22。

should return "3x", not "22" as it is now.

某些东西像

for key in sorted(dict, ???key=lambda key: len(mydict[key])):

是在里面。

可以在一个字符串中做吗？

Just can't get what is inside.
Is it possible to do in one string?

推荐答案

>>> text = 'xxxx'
>>> d = {'xxx' : '3','xx' : '2'}
>>> for k in sorted(d, key=len, reverse=True): # Through keys sorted by length
        text = text.replace(k, d[k])


>>> text
'3x'

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