按值的长度对字典排序 [英] Sort a dictionary by length of the value

问题描述

我有字典:

d = {'a':[1,3], 'b':[3,4,5,6], 'c':[1], 'd':[1,2,3] }

我想用前两个key:value对制作一个较小的新字典，按值列表中的len排序.因此，在这种情况下，我想要:

I want to make a smaller, new dictionary with the top two key:value pairs, sorted by the len of the lists in value. So in this case, I want:

newd = {'b':[3,4,5,6], 'd':[1,2,3] }

我尝试了此答案，但出现了以下错误:

I tried this answer but got this error:

NameError: global name 'd' is not defined

推荐答案

一种方法是根据值的长度对项目进行排序，然后从最后两个项目创建字典.

One approach is to sort the items according to length of value, and then create a dictionary from the last two items.

sorted_items = sorted(d.items(), key = lambda item : len(item[1]))
newd = dict(sorted_items[-2:])

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