如何按值对Python字典排序? [英] How to sort a Python dictionary by value?

问题描述

可能重复:
在Python中如何按字典值对字典列表进行排序?
基于嵌套字典值对Python字典进行排序

Possible Duplicate:
In Python how do I sort a list of dictionaries by values of the dictionary?
Sorting Python dictionary based on nested dictionary values

我有以下形式的字典:

a_dict = { 'e': (1, 100), 'a': (2, 3) }

我无法按元组的第二个元素对其进行排序.生成的字典将显示如下:

I am unable to sort it by the second element of the tuple. The resultant dictionary will appear as below:

a_dict = { 'a': (2, 3), 'e': (1, 100) }

推荐答案

字典不能像这样排序，但是您可以对它们的内容进行排序:

Dictionaries can't be sorted as such, but you can sort their contents:

sorted(a_dict.items(), key=lambda (k, (v1, v2)): v2)
sorted(a_dict.items(), key=lambda item: item[1][1])    # Python 3

您可以将结果放入 collections.OrderedDict (自2.7开始):

You can put the results into a collections.OrderedDict (since 2.7):

OrderedDict(sorted(a_dict.items(), key=lambda (k, (v1, v2)): v2))
OrderedDict(sorted(a_dict.items(), key=lambda item: item[1][1])    # Python 3

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