Python - 组合两个字典,连接字符串值? [英] Python - Combine two dictionaries, concatenate string values?
问题描述
相关:是否有任何pythonic方法来组合两个dicts(添加两个键出现的值)?
我想合并两个字符串:字符串字典,并连接值。上面的帖子建议使用 collections.Counter
,但它不处理字符串连接。
>>>从集合导入计数器
>>>> a = Counter({'foo':'bar','baz':'bazbaz'})
>>> b = Counter({'foo':'baz'})
>>> a + b
追溯(最近的最后一次呼叫):
文件< stdin>,第1行,< module>
文件/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/collections.py,第569行,__add__
TypeError:不能连接str和 int'对象
(我的猜测是尝试设置 b ['baz ']
to 0。)
我想获得 {'foo':'barbaz ','baz':'bazbaz'}
。连接顺序与我无关。什么是干净的,Pythonic的方法?
Dict-comprehension:
>>> d = {'foo':'bar','baz':'bazbaz'}
>>> d1 = {'foo':'baz'}
>>> keys = d.viewkeys()| d1.viewkeys()
>>> {k:d.get(k,'')+ d1.get(k,'')for k in key}
{'foo':'barbaz','baz':'bazbaz'}
对于Python 2.6及更早版本:
>>>对于键中的k,可以使用(k,d.get(k,'')+ d1.get(k,''))
{'foo':'barbaz','baz':'bazbaz' }
这将适用于任何数量的数字:
$ b $
返回{k:.join(dic。 get(k,'')for dic in dictions)for k in keys}
...
>>> d = {'foo':'bar','baz':'bazbaz'}
>>> d1 = {'foo':'baz','spam':'eggs'}
>>> d2 = {'foo':'foofoo','spam':'bar'}
>>> func(d,d1,d2)
{'foo':'barbazfoofoo','baz':'bazbaz','spam':'eggsbar'}
pre>
Related: Is there any pythonic way to combine two dicts (adding values for keys that appear in both)?
I'd like to merge two string:string dictionaries, and concatenate the values. Above post recommends using collections.Counter
, but it doesn't handle string concatenation.
>>> from collections import Counter
>>> a = Counter({'foo':'bar', 'baz':'bazbaz'})
>>> b = Counter({'foo':'baz'})
>>> a + b
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/collections.py", line 569, in __add__
TypeError: cannot concatenate 'str' and 'int' objects
(My guess is Counter tries to set b['baz']
to 0.)
I'd like to get a result of {'foo':'barbaz', 'baz':'bazbaz'}
. Concatenation order doesn't matter to me. What is a clean, Pythonic way to do this?
Dict-comprehension:
>>> d = {'foo': 'bar', 'baz': 'bazbaz'}
>>> d1 = {'foo': 'baz'}
>>> keys = d.viewkeys() | d1.viewkeys()
>>> {k : d.get(k, '') + d1.get(k, '') for k in keys}
{'foo': 'barbaz', 'baz': 'bazbaz'}
For Python 2.6 and earlier:
>>> dict((k, d.get(k, '') + d1.get(k, '')) for k in keys)
{'foo': 'barbaz', 'baz': 'bazbaz'}
This will work for any number of dicts:
def func(*dicts):
keys = set().union(*dicts)
return {k: "".join(dic.get(k, '') for dic in dicts) for k in keys}
...
>>> d = {'foo': 'bar', 'baz': 'bazbaz'}
>>> d1 = {'foo': 'baz','spam': 'eggs'}
>>> d2 = {'foo': 'foofoo', 'spam': 'bar'}
>>> func(d, d1, d2)
{'foo': 'barbazfoofoo', 'baz': 'bazbaz', 'spam': 'eggsbar'}
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