如何重置字典中的所有值 [英] How to reset all values in a dictionary
问题描述
,dan:0,Lewis:0,NewAccount2:0,testyear3:1,testyear6:0,NewAccount1:0,testyear4:0,testyear5 Matt1:0,swag:1,lewis:1,matt:1,notin:0}
这是定义为completeddict的字典。
我想做的是改变所有的值,无论他们调用什么值为0.
但是请记住,新的帐号将被添加到任何一个键,所以我不能手动dodonedict [green] = 0,finisheddict [lewis] = 0等等。
有没有办法让python更改字典中的所有值返回0?
编辑:不幸的是我不想创建一个新的字典 - 我想保持它被称为completeddict,因为程序需要使用定义的字典作为程序中的许多点的完成。
另一个选项是使用 .fromkeys()
:
fromkeys(seq [,value])
使用seq和值设置为值。
d = d.fromke ys(d,0)
演示:
>>> d = {green:0,y3:1,m @ tt:0,newaccount:0,egg:0,results:0,dan:0,Lewis :0,NewAccount2:0,testyear3:1,testyear6:0,NewAccount1:0,testyear4:0,testyear5:0,Matt1:0,swag ,lewis:1,matt:1,notin:0}
>>> d.fromkeys(d,0)
{'newaccount':0,'swag':0,'notin':0,'NewAccount1':0,'Matt1':0,'testyear4' Lewis':0,'dan':0,'matt':0,'results':0,'m @ tt':0,'green':0,'testyear5':0,'lewis' NewAccount2':0,'y3':0,'testyear3':0,'egg':0,'testyear6':0}
{"green": 0, "y3": 1, "m@tt": 0, "newaccount": 0, "egg": 0, "results": 0, "dan": 0, "Lewis": 0, "NewAccount2": 0, "testyear3": 1, "testyear6": 0, "NewAccount1": 0, "testyear4": 0, "testyear5": 0, "Matt1": 0, "swag": 1, "lewis": 1, "matt": 1, "notin": 0}
this is the dictionary defined as 'completeddict'. What I want to do, is to change ALL values no matter what they are called to 0. However bear in mind that new account names will be added at any point as 'keys' so I cannot manually do "completeddict[green] = 0", "completeddict[lewis] = 0", etc etc.
Is there any way to have python change ALL values within a dictionary back to 0?
EDIT: Unfortunately I do not want to create a new dictionary - I want to keep it called 'completeddict' as the program needs to use the dictionary defined as 'completeddict' at many points in the program.
Another option is to use .fromkeys()
:
fromkeys(seq[, value])
Create a new dictionary with keys from seq and values set to value.
d = d.fromkeys(d, 0)
Demo:
>>> d = {"green": 0, "y3": 1, "m@tt": 0, "newaccount": 0, "egg": 0, "results": 0, "dan": 0, "Lewis": 0, "NewAccount2": 0, "testyear3": 1, "testyear6": 0, "NewAccount1": 0, "testyear4": 0, "testyear5": 0, "Matt1": 0, "swag": 1, "lewis": 1, "matt": 1, "notin": 0}
>>> d.fromkeys(d, 0)
{'newaccount': 0, 'swag': 0, 'notin': 0, 'NewAccount1': 0, 'Matt1': 0, 'testyear4': 0, 'Lewis': 0, 'dan': 0, 'matt': 0, 'results': 0, 'm@tt': 0, 'green': 0, 'testyear5': 0, 'lewis': 0, 'NewAccount2': 0, 'y3': 0, 'testyear3': 0, 'egg': 0, 'testyear6': 0}
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