嵌套字典 [英] Nested dictionary

问题描述

我正在处理一些类似FASTA的序列（不是FASTA，但是我已经定义了与PISCES服务器的一些被剔除的PDB相似的东西）。

I am working on some FASTA-like sequences (not FASTA, but something I have defined that's similar for some culled PDB from the PISCES server).

我有一个问题。我有一个名为 nCatSeq 的序列的小号，其中有MULTIPLE nBasinSeq 。我经历了一个大型的PDB文件，我想提取每个 nCatSeq 相应的 nBasinSeq 而不会在字典中有冗余。下面给出了代码片段。

I have a question. I have a small no of sequences called nCatSeq, for which there are MULTIPLE nBasinSeq. I go through a large PDB file and I want to extract for each nCatSeq the corresponding nBasinSeq without redundancies in a dictionary. The code snippet that does this is given below.

nCatSeq=item[1][n]+item[1][n+1]+item[1][n+2]+item[1][n+3]
nBasinSeq=item[2][n]+item[2][n+1]+item[2][n+2]+item[2][n+3]
if nCatSeq not in potBasin:
    potBasin[nCatSeq]=nBasinSeq
else:   
    if nBasinSeq not in potBasin[nCatSeq]:
        potBasin[nCatSeq]=potBasin[nCatSeq],nBasinSeq
    else:
        pass

我得到以下内容作为一个nCatSeq的答案，

I get the following as the answer for one nCatSeq,

'4241': ((('VUVV', 'DDRV'), 'DDVG'), 'VUVV')

我想要的是：

'4241'：（'VUVV'，'DDRV'，'DDVG'，'VUVV' p>

'4241': ('VUVV', 'DDRV', 'DDVG', 'VUVV')

由于以下命令，我不想要所有的额外括号

I don't want all the extra brackets due to the following command

potBasin[nCatSeq]=potBasin[nCatSeq],nBasinSeq 

见上面的代码片段）

有没有办法这样做？

推荐答案

您可以将它们添加为元组：

You can add them as tuples:

if nCatSeq not in potBasin:
    potBasin[nCatSeq] = (nBasinSeq,)
else:
    if nBasinSeq not in potBasin[nCatSeq]:
        potBasin[nCatSeq] = potBasin[nCatSeq] + (nBasinSeq,)

这样，而不是：

(('VUVV', 'DDRV'), 'DDVG')
# you will get
('VUVV', 'DDRV', 'DDVG') # == ('VUVV', 'DDRV')+ ('DDVG',)

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