如何平铺嵌套的python字典? [英] How to flatten nested python dictionaries?
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问题描述
我试图平铺嵌套字典:
dict1 = {
'Bob': {
'shepherd': [4, 6, 3],
'collie': [23, 3, 45],
'poodle': [2, 0, 6],
},
'Sarah': {
'shepherd': [1, 2, 3],
'collie': [3, 31, 4],
'poodle': [21, 5, 6],
},
'Ann': {
'shepherd': [4, 6, 3],
'collie': [23, 3, 45],
'poodle': [2, 10, 8],
}
}
我想在列表中显示所有值:
[4,6,3,23,3,45,2,0,6,1,2, 3,...,2,10,8]
I'd like to display all values in lists: [4, 6, 3, 23, 3, 45, 2, 0, 6, 1, 2, 3,..., 2, 10, 8]
我的第一个想法是这样做:
My first idea was to do in this way:
dict_flatted = [ i for name in names.values() for dog in dogs.values() for i in dog]
尽管我收到错误。
推荐答案
您可以使用简单的递归函数,如下所示。 >
You can use a simple recursive function as follows.
def flatten(d):
res = [] # Result list
if isinstance(d, dict):
for key, val in d.items():
res.extend(flatten(val))
elif isinstance(d, list):
res = d
else:
raise TypeError("Undefined type for flatten: %s"%type(d))
return res
dict1 = {
'Bob': {
'shepherd': [4, 6, 3],
'collie': [23, 3, 45],
'poodle': [2, 0, 6],
},
'Sarah': {
'shepherd': [1, 2, 3],
'collie': [3, 31, 4],
'poodle': [21, 5, 6],
},
'Ann': {
'shepherd': [4, 6, 3],
'collie': [23, 3, 45],
'poodle': [2, 10, 8],
}
}
print( flatten(dict1) )
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