使用java.util.zip.ZipOutputStream时zip文件中的目录 [英] directories in a zip file when using java.util.zip.ZipOutputStream

问题描述

假设我有一个文件t.txt，一个目录t和另一个文件t / t2.txt。如果我使用linux zip实用程序zip -r t.zip t.txt t，我得到一个ZIP文件，其中包含以下条目（unzip -l t.zip）：

 存档：t.zip 
长度日期时间名称
 -------- ---- ---- --- -  
 9 04-11-09 09:11 t.txt 
 0 04-11-09 09:12 t / 
 15 04-11-09 09:12 t / t2.txt 
 -------- ------- 
 24 3个文件
  

如果我尝试使用java.util.zip.ZipOutputStream复制该行为，并为目录创建一个zip条目，则java会抛出异常。它只能处理文件。我可以在zip文件中创建一个t / t2.txt条目，并添加t2.txt文件内容，但是我无法创建目录。为什么是这样？

解决方案

看起来ZipOutputStream不能处理空目录，但你有一个文件，所以它不空。尝试（ from ）

  public class Test {
 public static void main（String [] args）{
 try {
 FileOutputStream f = new FileOutputStream（test 。压缩）; 
 ZipOutputStream zip = new ZipOutputStream（new BufferedOutputStream（f））; 
 zip.putNextEntry（new ZipEntry（xml /））; 
 zip.putNextEntry（new ZipEntry（xml / xml））; 
 zip.close（）; 
} catch（Exception e）{
 System.out.println（e.getMessage（））; 
} 
} 
} 
  

Lets say I have a file t.txt, a directory t and another file t/t2.txt. If I use the linux zip utility "zip -r t.zip t.txt t", I get a zip file with the following entries in them (unzip -l t.zip):

Archive:  t.zip
  Length     Date   Time    Name
 --------        ----      ----      ----
        9  04-11-09 09:11   t.txt
        0  04-11-09 09:12   t/
      15  04-11-09 09:12   t/t2.txt
 --------                           -------
       24                          3 files

If I try to replicate that behavior with java.util.zip.ZipOutputStream and create a zip entry for the directory, java throws an exception. It can handle only files. I can create a t/t2.txt entry in the zip file and add use the t2.txt file contents to it but I can't create the directory. Why is that?

解决方案

It looks like ZipOutputStream can't handle empty directories, but you have a file in there so its not empty. Try (from)

public class Test {
    public static void main(String[] args) {
        try {
            FileOutputStream f = new FileOutputStream("test.zip");
            ZipOutputStream zip = new ZipOutputStream(new BufferedOutputStream(f));
            zip.putNextEntry(new ZipEntry("xml/"));
            zip.putNextEntry(new ZipEntry("xml/xml"));
            zip.close();
        } catch(Exception e) {
            System.out.println(e.getMessage());
        }
    }
}

这篇关于使用java.util.zip.ZipOutputStream时zip文件中的目录的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！