Python无法获取文件的完整路径名 [英] Python cant get full path name of file

问题描述

尝试在我的驱动器上钻取一个包含子折叠的目录。当我找到我正在寻找的文件扩展名的文件时，我想要完整的文件路径。现在这是我有的：

Trying to drill through a directory on my drive that has subfoldrs within it. When I find files that have the file extensions I'm looking for I want the full file path. Right now this is what I have:

import os
import Tkinter
import tkFileDialog
from Tkinter import Tk
from tkFileDialog import askopenfilename

root = Tkinter.Tk().withdraw()
dirname = tkFileDialog.askdirectory(initialdir='.')

list = [] 


for root, dirs, files in os.walk(dirname):
    for name in files:
        if name.find(".txt") != -1:
           name = str(name)
           name = os.path.realpath(name)
           list.append(name)

print list

返回

c:\users\name\desktop\project\file.txt

然而，file.txt位于

however that file.txt is located in

c:\users\name\desktop\project\folder1\file.txt

推荐答案

您可能需要加入文件名包含它的目录：

You probably need to join the filename with the directory that contains it:

os.path.realpath(os.path.join(root,name))

eg我刚刚测试过：

import os
for root, dirs, files in os.walk('.'):
    for name in files:
        if name == 'foo':
           name = str(name)
           name = os.path.realpath(os.path.join(root,name))
           print name

具有以下目录结构：

test
  + foo
  + test2
     + foo

，并正常运作。

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