Lua Require函数的完整路径名 [英] Lua Require function on a full path name

问题描述

我需要在lua文件上调用require，而lua文件不会总是在同一位置.我试图在完整路径名上调用require，但这似乎也不起作用.我什至尝试用正确的完整路径名替换同一文件的正常工作要求

I need to call the require on a lua file that will not always be in the same place. I was trying to call require on the full path name but that doesn't seem to be working either. I even tried replacing one of my working normal requires with a correct full path name to the same file

示例更改 需要"foo" 到 需要"C:\ Users \ Me \ MyLuaProject \ foo"

example changing require "foo" to require "C:\Users\Me\MyLuaProject\foo"

但是当我将其切换为完整路径名时，它不再能找到它.因此，我想知道您是否甚至可以在完整路径上调用require，如果不能，我将如何以不同的方式实现相同的结果?

but when i switched it to the full path name it could no longer find it. So I am wondering if you can even call require on a full path and if not how would i achieve the same result differently?

推荐答案

将包含文件的目录添加到

Add the directory containing the file to package.path:

package.path = package.path .. ";C:\\Users\\Me\\MyLuaProject"
require "foo"

您也可以将其添加到LUA_PATH环境变量中，但这可能不太容易即时修改.

You can also add it to the LUA_PATH environment variable, but this is probably less easy to modify on the fly.

模块的常见模式是具有abc.lua和abc/xyz.lua；要在这样的子目录中需要文件，请使用以下命令:

A common pattern for modules is to have abc.lua and abc/xyz.lua; to require files in a subdirectory like that, use the following:

require "abc"
require "abc.xyz"

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