检查具有完整路径名的文件是否存在时的二元运算符预期错误 [英] binary operator expected error when checking if a file with full pathname exists

问题描述

pathname=$(cat $HOME/.rm.cfg)
if [ ! -z $pathname/$1 ]

.rm.cfg 是一个包含以下目录的文件

.rm.cfg is a file that contains the following directory

/home/用户名/deleted1

/home/username/deleted1

$1 是文件名，例如.玻璃

$1 is the name of a file eg. glass

如果 [ !-z $pathname/$1 ] 给出二元运算符预期错误.

why does the line if [ ! -z $pathname/$1 ] give a binary operator expected error.

推荐答案

看起来您的 $pathname 包含不止一个词..rm.cfg 文件中可能有多行，或者路径可能包含空格.无论如何，你最终得到

Looks like your $pathname includes more than one word. Could be multiple lines in your .rm.cfg file, or perhaps the path includes spaces. Anyway, you end up with

if [ ! -z word word word/$1 ]

这不好.如果您只需要一条路径并希望防止路径包含空格，请将 if 行更改为

which is no good. If you're just expecting a single path and want to protect against the path containing whitespace, change your if line to

if [ ! -z "$pathname/$1" ]

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