分页Django表单 [英] Paginate Django formset
问题描述
paginator = Paginator(formset,10)
。这样做的正确方法是什么,如果有办法?这是一个我发现的解决方案的通用示例我的问题:
在 forms.py
文件中:
$ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ $ / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / / code>
在 views.py
文件中:
FormSet = modelformset_factory(MyModel,form = MyForm,extra = 0)
如果request.method =='POST':
formset = FormSet(request.POST,request.FILES)
#你的验证和其余的'POST'代码
else:
query = MyModel.objects.filter(condition)
paginator = Paginator(查询,10)#每页显示10个表单
page = request.GET.get('page')
try:
objects = paginator.page(page)
除了PageNotAnInteger:
objects = paginator.page(1)
exc ept EmptyPage:
objects = paginator.page(paginator.num_pages)
page_query = query.filter(id__in = [object.id for objects in objects])
formset = FormSet(queryset = page_query )
context = {'objects':objects,'formset':formset}
return render_to_response('template.html',context,
context_instance = RequestContext(request))
您需要使用当前页面中的对象创建表单集,否则,当您尝试执行 formset = FormSet(request.POST,request.FILES)
在POST方法中,Django引发了MultiValueDictKeyError错误。
code> template.html file:
{%if objects%}
< form action =method =post>
{%csrf_token%}
{{formset.management_form}}
{form for formset.forms%}
{{form.id}}
< ;! - 显示每个表单 - >
{{form.as_p}}
{%endfor%}
< input type =submitvalue =保存/>
< / form>
< div class =pagination>
< span class =step-links>
{%if objects.has_previous%}
< a href =?page = {{objects.previous_page_number}}>上一个< / a>
{%endif%}
< span class =current>
{{objects.paginator.num_pages}}的{{objects.number}}}
< / span>
{%if objects.has_next%}
< a href =?page = {{objects.next_page_number}}> next< / a>
{%endif%}
< / span>
< / div>
{%else%}
< p>没有对象。< / p>
{%endif%}
I have a model formset that I want to display 10 forms at a time using Django's Paginator, but it can't be done like paginator = Paginator(formset, 10)
. What's the correct way to do this, if there is a way?
This is a generic example of the solution I found to my problem:
In the forms.py
file:
class MyForm(ModelForm):
class Meta:
model = MyModel
fields = ('description',)
In the views.py
file:
FormSet = modelformset_factory(MyModel, form=MyForm, extra=0)
if request.method == 'POST':
formset = FormSet(request.POST, request.FILES)
# Your validation and rest of the 'POST' code
else:
query = MyModel.objects.filter(condition)
paginator = Paginator(query, 10) # Show 10 forms per page
page = request.GET.get('page')
try:
objects = paginator.page(page)
except PageNotAnInteger:
objects = paginator.page(1)
except EmptyPage:
objects = paginator.page(paginator.num_pages)
page_query = query.filter(id__in=[object.id for object in objects])
formset = FormSet(queryset=page_query)
context = {'objects': objects, 'formset': formset}
return render_to_response('template.html', context,
context_instance=RequestContext(request))
You need to create the formset with the objects in the present page, otherwise, when you try to do formset = FormSet(request.POST, request.FILES)
in the POST method, Django raises a MultiValueDictKeyError error.
In the template.html
file:
{% if objects %}
<form action="" method="post">
{% csrf_token %}
{{ formset.management_form }}
{% for form in formset.forms %}
{{ form.id }}
<!-- Display each form -->
{{ form.as_p }}
{% endfor %}
<input type="submit" value="Save" />
</form>
<div class="pagination">
<span class="step-links">
{% if objects.has_previous %}
<a href="?page={{ objects.previous_page_number }}">Previous</a>
{% endif %}
<span class="current">
Page {{ objects.number }} of {{ objects.paginator.num_pages }}
</span>
{% if objects.has_next %}
<a href="?page={{ objects.next_page_number }}">next</a>
{% endif %}
</span>
</div>
{% else %}
<p>There are no objects.</p>
{% endif %}
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