Django中的弹性分页 [英] Flexible pagination in Django

问题描述

我想实现分页，这样我可以允许用户选择每页的记录数，例如10,25,50等。我该怎么做？有一个应用程序可以添加到我的项目中吗？

I'd like to implement pagination such that I can allow the user to choose the number of records per page such as 10, 25, 50 etc. How should I go about this? Is there an app I can add onto my project to do this?

谢谢

推荐答案

Django内置了一个Paginator对象。这是一个非常简单的API使用。使用两个参数实例化一个 Paginator 类：列表和每个页面的条目数。我将在底部粘贴一些示例代码。

Django has a Paginator object built into core. It's a rather straightforward API to use. Instantiate a Paginator class with two arguments: the list and the number of entries per "page". I'll paste some sample code at the bottom.

在您的情况下，您希望允许用户选择每页计数。您可以将每页计数作为URL的一部分（即，您的/ page / 10 /），也可以使其成为查询字符串（即/ your / page /？p = 10）。

In your case you want to allow the user to choose the per-page count. You could either make the per-page count part of the URL (ie. your/page/10/) or you could make it a query string (ie. your/page/?p=10).

某些东西...

# Assuming you're reading the Query String value ?p=
try:
    per_page = int(request.REQUEST['p'])
except:
    per_page = 25     # default value

paginator = Paginator(objects, per_page)

以下是Django文档页面中的一些示例代码，供Paginator更好地查看如何运作。

Here's some sample code from the Django doc page for the Paginator to better see how it works.

>>> from django.core.paginator import Paginator
>>> objects = ['john', 'paul', 'george', 'ringo']
>>> p = Paginator(objects, 2)

>>> p.count
4
>>> p.num_pages
2
>>> p.page_range
[1, 2]

>>> page1 = p.page(1)
>>> page1
<Page 1 of 2>
>>> page1.object_list
['john', 'paul']

这篇关于Django中的弹性分页的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！