Django模板对象类型 [英] Django template object type

问题描述

好吧，这是我的情况。我有一个通用对象的数组，我在django模板中迭代。那些对象有一些子类，我想在模板中找出我正在处理的子类。这可能吗？建议吗？

代码可能看起来像（if语句包含一些虚构语法）的一些内容：

 <表> 
< tr> 
< th> name< / th> 
< th>首页< / th> 
< / tr> 
 {％for fridge％} 
< tr> 
< td> 
 {{beer.name}} 
< / td> 
< td> 
 {％如果啤酒是国内的实例％}美国的A {％endif％} 
 {％如果啤酒是导入的实例％}其他地方{％endif％} 
< / TD> 
< / tr> 
 {％endfor％} 
< / table> 
  

解决方案

这是一个旧问题，但是FWIW可以做这个与模板过滤器。

  @ register.filter 
 def classname（obj）：
 return obj .__ class __.__ name__ 
  

然后在你的模板中你可以做：

  {％with beer | classname as modelclass％} 
 {％如果modelclass ==国内％} US $ A 
 {％elif modelclass ==Import％}其他地方
 {％endif％} 
 {％endwith％} 
  

Alright, here's my situation. I've got an array of generic objects that I'm iterating over in a django template. Those objects have a number of subclasses and I want to figure out in the template which subclass I'm dealing with. Is this possible? Advisable?

The code might look something along the lines of (where the if statements include some imaginary syntax):

<table>
   <tr>
      <th>name</th>
      <th>home</th>
   </tr>
   {% for beer in fridge %}
   <tr>
      <td>
         {{ beer.name }}
      </td>
      <td>
          {% if beer is instance of domestic %}US of A{% endif %}
          {% if beer is instance of import %}Somewhere else{% endif %} 
      </td>
   </tr>
   {% endfor %}
</table>

解决方案

This is an old question, but FWIW you can do this with a template filter.

@register.filter
def classname(obj):
    return obj.__class__.__name__

Then in your template you can do:

{% with beer|classname as modelclass %}
{% if modelclass == "Domestic" %}US of A
{% elif modelclass == "Import" %}Somewhere else
{% endif %}
{% endwith %}

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