通过Django模板标记渲染JSON对象 [英] Render JSON objects through Django template-tag

问题描述

我通过AJAX在模板中以JSON格式收到Django对象的字典。有没有可能通过Django模板标签来呈现这个字典？我可以从jQuery调用Django模板标签，并将对象作为参数传递给它吗？

目前的解决方案是在jQuery中乏味地构造html：

  $。ajax（{
 url：url，
 type：POST，
 success： function（data）{
 var obj = $ .parseJSON（data）; 
 $ .each（obj，function（）{
 data = this ['fields']; 
 
 post + =< p id ='+ this ['pk'] +'>+ data ['creator'] + data ['created'] + data ['body']; 
 post + =depth：+ data ['depth']; 
 post + =< a name ='+ this ['pk'] +'class ='show_answers'href ='+ show_url +'>显示< / a>; 
 post + =< a name ='+ this ['pk'] +'href ='+ answer_url + '>答案< / a>< / p>; 
 post + =< div id ='+ this ['pk'] +_div'>< / div>; 
}）; 
 $（'＃ + div_id）html的（后）; 
}，
跨域：假
}）; 
  

解决方案

Templatetags是服务器端，所以不，你不能使用Django的模板来处理Ajax请求的结果 - 而不是直接最少。可能的解决方案：

• 您最终可以写，将采取你的JSON数据并返回的HTML格式的视图，但是这将是沉重的一面了一下。




• 如果JSON是来自自己的应用程序，你可以返回一个HTML片段，而不是JSON。




• 如果json来自另一个网站，您还可以在应用程序中查看请求，并从json返回一个格式化的html片段（然后你最后，如果你的应用程序在ajax / json的东西很沉重，你可能想使用一些js模板框架或者像angular.js

I receive a dictionary of Django objects in a JSON format via AJAX in the template. Is there any possibility to render this dictionary through a Django template-tag? Can I call a Django template-tag from jQuery and transfer the object as a parameter to it?

The current solution is to tediously construct the html in jQuery:

$.ajax({
    url: url,
    type: "POST",
    success: function(data) {
        var obj = $.parseJSON(data);
        $.each(obj, function() {
            data = this['fields'];

            post += "<p id='" + this['pk'] + "'>" + data['creator'] + data['created'] + data['body'];
            post += "depth: " + data['depth'];
            post += "<a name='" + this['pk'] + "' class='show_answers' href='" + show_url + "'>Show</a>";
            post += "<a name='" + this['pk'] + "' href='" + answer_url + "'>Answer</a></p>";
            post += "<div id='" + this['pk'] + "_div'></div>";
        });
        $('#' + div_id).html(post);
    },
    crossDomain: false
}); 

解决方案

Templatetags are server-side, so no, you cannot use django's templating to handle the result of an Ajax request - not directly at least. Possible solutions :

• you can eventually write a view that would take your json data and returns formatted html, but that's going to be a bit on the heavy side.

• if the json comes from your own application, you could return an html fragment instead of json.

• if the json comes from another site, you could also have a view in your app doing the request and returning a formatted html fragment from the json (then you'd post to this view).

• finally if you're app is heavy on ajax/json stuff, you may want to use some js templating framework or something like angular.js

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