根据所选父母显示子节点 [英] show children nodes depending on selected parent

问题描述

我一直在寻找，找不到答案。我只有3个月的使用python / django的经验，所以借口我的虚疑！
我使用django mptt显示一个简单的嵌套集导航。

 < ul class =root> 
 {％recursetree nodes％} 
< li> 
 {{node.name}} 
 {％if not node.is_leaf_node％} 
< ul class =children> 
 {{children}} 
< / ul> 
 {％endif％} 
< / li> 
 {％endrecursetree％} 
  

这个功能很好 - 但是我只想显示所选类别的孩子（基于slug），而不是全部显示。
任何想法？

---

我终于这样做了：

  {％recursetree nodes％} 
< li> 
< a href ='/ {{node.get_absolute_url}}'> {{node.name}}< / a> 
< / li> 
 {％if not node.is_leaf.node％} 
 {％for c in child％} 
 {％if c in node.get_children％} 
 {％if forloop。 first％} 
< ul class =children> 
 {{children}} 
< / ul> 
 {％endif％} 
 {％endif％} 
 {％endfor％} 
 {％endif％} 
 
 
 
 {％endrecursetree％} 
  

在视图

  category = get_object_or_404（Category，slug = slug）
 child = category.get_children（）
如果不是孩子：
 child = category.get_siblings （）
  

但它是一个黑客。有人有更好的主意吗？

解决方案

您需要发送关于您所在节点的一些信息，然后是一个简单的如果语句。

关于如何普遍地发送节点信息，有几种方法可以在Django中执行此操作，没有他们是完美的。我的首选方法是上下文处理器： http ：//docs.djangoproject.com/en/1.3/ref/templates/api/#writing-your-own-context-processors

Hi i've been looking all over and can't find the answer to this. I have only 3 months experience in using python/django so excuse my dummy quesion! Im using django mptt to display a simple nested set navigation.

<ul class="root">
{% recursetree nodes %}
    <li>
        {{ node.name }}
        {% if not node.is_leaf_node %}
            <ul class="children">
                {{ children }}
            </ul>
        {% endif %}
    </li>
{% endrecursetree %}

this works fine - however i would like to show only children of the selected category (based on slug) and not all of them. Any ideas ???

---

i finally did it like this:

{% recursetree nodes %}
    <li>
      <a href='/{{ node.get_absolute_url}}'>{{ node.name }}</a>
    </li>
       {% if not node.is_leaf.node %}
                {% for c in child %}
                        {% if c in node.get_children  %}
                                {% if forloop.first %}
                                   <ul class="children">
                                         {{ children }}
                                            </ul>
                                {% endif %}
                        {% endif %}
                {% endfor %}
        {% endif %}   



{% endrecursetree %}          

in views

category = get_object_or_404(Category, slug=slug)
child = category.get_children()
if not child : 
      child = category.get_siblings() 

but it is a hack. has anyone got better idea?

解决方案

You need to send down some information about what node you're in, and then it's a simple if statement.

Regarding how to send down the node information universally, there are a couple ways to do this in Django, and none of them are perfect. My preferred method is context processors: http://docs.djangoproject.com/en/1.3/ref/templates/api/#writing-your-own-context-processors

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