在Django 1.8中手动提交 [英] Manual commit in Django 1.8

问题描述

如何在Django 1.8中实现 @commit_manually

我正在尝试升级Django 1.5代码与Django 1.8一起工作，出于一些奇怪的原因，Django 1.6中没有直接替换， c> commit_manually 装饰器已被删除。我的进程遍历数千条记录，所以它不能将整个进程包装在单个事务中，而不会耗尽内存，但它仍然需要在事务中分组一些记录以提高性能。为了做到这一点，我有一个包含@commit_manually的方法，每次N次迭代都调用transaction.commit（）。

我从 docs ，但这似乎仍然受支持。我只需要调用 set_autocommit（False）而不是方便的装饰器。这是否正确？

解决方案

是的，你已经有了。调用 set_autocommit（False）开始一个事务，然后调用 commit（）和 set_autocommit

您可以将其包装在自己的装饰器中：

set_autocommit（False）
res = fn（*）
def _commit_manually（* args，** kwargs） args，** kwargs）
commit（）
set_autocommit（True）
return res
return _commit_manually

How do you implement @commit_manually in Django 1.8?

I'm trying to upgrade Django 1.5 code to work with Django 1.8, and for some bizarre reason, the commit_manually decorator was removed in Django 1.6 with no direct replacement. My process iterates over thousands of records, so it can't wrap the entire process in a single transaction without running out of memory, but it still needs to group some records in a transaction to improve performance. To do this, I had a method wrapped with @commit_manually, which called transaction.commit() every N iterations.

I can't tell for sure from the docs, but this still seems supported. I just have to call set_autocommit(False) instead of having a convenient decorator. Is this correct?

解决方案

Yeah, you've got it. Call set_autocommit(False) to start a transaction, then call commit() and set_autocommit(True) to commit it.

You could wrap this up in your own decorator:

def commit_manually(fn):
    def _commit_manually(*args, **kwargs):
        set_autocommit(False)
        res = fn(*args, **kwargs)
        commit()
        set_autocommit(True)
        return res
    return _commit_manually

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