如何构建一个get_admin_url / get app_label和类名？ [英] How to construct a get_admin_url / get app_label and class name?

问题描述

我有一个模型方法 _get_admin_url ，并想动态构建网址。

I've got a model method _get_admin_url and want to construct the url dynamically.

class Person(models.Model):
    ...

    def _get_admin_url(self):
        "Returns the admin url."
        # return '/admin/some_app/person/%d' %self.id
        return '/admin/%s/%s/%d/' %(..., ..., d)

    admin_url = property(_get_admin_url)

如何获取app_label和类名的值？还是有更好的方法？

How can I get the values for app_label and class name? Or is there a better way?

推荐答案

您可以使用 反转管理URL 功能

You can use the Reversing admin URLs feature

from django.core import urlresolvers
c = Choice.objects.get(...)
change_url = urlresolvers.reverse('admin:polls_choice_change', args=(c.id,))

如果你想参考change_list页面，你会做

If you wish to refer the change_list page, you would do

urlresolvers.reverse('admin:%s_%s_changelist' % (app_label, model_name))

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