django表单和ModelMultipleChoiceField处理现有记录时 [英] django forms and ModelMultipleChoiceField when working with existing records

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问题描述



我有什么我想做的事情我觉得很常见,但我真的不确定如何解决这个问题。目前,我在我的表单上生成了一个复选框列表(使用CheckboxSelectMultiple),该列表自动勾选django中所有用户列表中所有member的用户(由queryset = User.objects.all())。



我想要实际做什么:我不想列出Django中的每个用户,我只想显示一个用户列表在会员。



我认为可以做到这一点:我想我可以通过将查询器修改为project.members.all ()其中project = Project(项目的具体实例)。但是我如何将这个上下文传递给我的表单?

 #models.py 
class Project(models.Model) :
name = models.CharField(max_length = 100)
members = models.ManyToManyField(User,related_name =members,blank = True,null = True)


#forms.py
class ProjectSettings(forms.Form):
summary = forms.CharField(max_length = 200)
members = forms.ModelMultipleChoiceField(queryset = User.objects.all (),widget = forms.CheckboxSelectMultiple())


#template snippet
< form method =postaction =/ projects / {{project.slug} } /设置/保存/>
{%表单中的字段%}
< div class =form-row>
{{field.errors}}
{{field.label_tag}} {{field}}
{%if field.help_text%}
< p class =help -text> {{field.help_text}}< / p>
{%endif%}
< / div>
{%endfor%}


#view.py
def update_project(request,project_slug):
如果request.method =='POST' :
form = ProjectSettings(request.POST)
如果form.is_valid():#所有验证规则通过
#处理form.cleaned_data中的数据
project.summary = form .cleaned_data ['summary']
project.members = form.cleaned_data ['members']
project.save()
return HttpResponseRedirect('/ projects /'+ project.slug +' /')
else:
data_dict = {'summary':project.summary''members':project.members.all()}
form = ProjectSettings(initial = data_dict)

return render_to_response('update_project.html',{'form':form},context_instance = RequestContext(request))

我希望这是有道理的,我道歉,因为我真的认为这是一个简单的我在这里错过 - 但是我没有能够找到一个具体的例子来展示如何用非模型表单来实现。



提前感谢,



Jamie

解决方案

我猜你正在从项目模型中留下一些东西。您的视图还将其中的项目调用为$ code> project.members.all()和 project.summary



假设您在项目模型中有一个摘要字段,如果要使用表单而不是模型表单,则:



forms.py

  class ProjectSettings(forms.Form):
summary = form.CharField(max_length = 200)

def __init __(self,qs = None,* args,** kwargs):
super(ProjectSettings,self).__ init __(* args,* * kwargs)
如果qs:
self.fields ['members'] = forms.ModelMultipleChoiceField(queryset = qs,widget = forms.CheckboxSelectMultiple())

并且在您的views.py中,您可以将qs传递到以下格式:

  def update_project(request,project_slug):
project = None
如果project_slug:
project = get_object_or_404(Project,name = project_slug)#某种程度上得到你的专业对象

qs = project.members.all()

如果request.method =='POST':
form = ProjectSettings(qs,request.POST )
如果form.is_valid():#所有验证规则通过
#处理form.cleaned_data中的数据
project.summary = form.cleaned_data ['summary']
项目.members = form.cleaned_data ['members']
project.save()
return HttpResponseRedirect('/ projects /'+ project.slug +'/')
else:
form = ProjectSettings(qs)

返回render_to_response('update_project.html',{'form':form},context_instance = RequestContext(request))

如果您的Project模型中确实有您的摘要字段,则使用ModelForm是有道理的。



forms.py:

  class ProjectSettings(forms.ModelForm):
def __init __(self,qs = None ,* args,** kwargs):
super(ProjectSettings,self).__ init __(* args,** kwargs)
self.fields ['members']。widget = forms.CheckboxSelectMultiple()
class Meta:
model = Project
fields =('summary','members')

py:

  def update_project(request,project_slug):
project = None
如果project_slug:
project = get_object_or_404(Project,name = project_slug)#以某种方式获取项目对象

如果request.method =='POST':
form = ProjectSettings(request.POST,instance =项目)
如果form.is_valid():#所有验证规则通过
#处理form.cleaned_data中的数据
project.save()
返回HttpResponseRedirect('/ projects / '+ project.slug +'/')
else:
form = ProjectSettings(instance = project)

返回render_to_response('update_projec t.html',{'form':form},context_instance = RequestContext(request))


I'm trying to do something which I would think is quite common, but I'm just really unsure how to tackle this.

What I currently do: Currently I produce a list of check boxes (using 'CheckboxSelectMultiple') on my form which auto ticks all the users who are in 'members' from the list of all Users in django (produced by "queryset=User.objects.all()").

What I want to actually do: I don't want to list every user in Django, I just want to show a list of Users in 'members'.

How I think it can be done: I think I can do this by modifying the queryset to be something like "project.members.all()" where project = Project (a specific instance of project). But how do I pass this context to my form?

# models.py
class Project(models.Model):
    name = models.CharField(max_length=100)
    members = models.ManyToManyField(User, related_name="members", blank=True, null=True)


# forms.py
class ProjectSettings(forms.Form):
    summary = forms.CharField(max_length=200)
    members = forms.ModelMultipleChoiceField(queryset=User.objects.all(), widget=forms.CheckboxSelectMultiple())


#template snippet
        <form method="post" action="/projects/{{ project.slug }}/settings/save/">
    {% for field in form %}
    <div class="form-row">
        {{ field.errors }}
        {{ field.label_tag }} {{ field }}
        {% if field.help_text %}
        <p class="help-text">{{ field.help_text }}</p>
        {% endif %}
    </div>
    {% endfor %}


# view.py
def update_project(request, project_slug):
    if request.method == 'POST':
        form = ProjectSettings(request.POST)
        if form.is_valid(): # All validation rules pass
            # Process the data in form.cleaned_data
            project.summary = form.cleaned_data['summary']
            project.members = form.cleaned_data['members']
            project.save()
            return HttpResponseRedirect('/projects/' + project.slug + '/')
    else:
        data_dict = {'summary': project.summary, 'members': project.members.all()}
        form = ProjectSettings(initial=data_dict)

    return render_to_response('update_project.html', {'form': form}, context_instance=RequestContext(request))

I hope this makes sense, and I do apologise as I really think this is something simple I'm missing here - but I haven't been able to find a specific example showing how to do this with non-model forms.

Thanks in advance,

Jamie

解决方案

I'm guessing that you are leaving some stuff out of your Project model. Your view is also calling project.members.all() and project.summary with out getting a project in the else statement.

Assuming that you have a summary field in the projects model, if you want to use a form and not a model form, then:

forms.py

class ProjectSettings(forms.Form):
    summary = forms.CharField(max_length=200)

    def __init__(self, qs=None, *args, **kwargs):
        super(ProjectSettings, self).__init__(*args, **kwargs)
        if qs:
            self.fields['members'] = forms.ModelMultipleChoiceField(queryset=qs, widget=forms.CheckboxSelectMultiple())

and in your views.py you would pass in the qs to the form:

def update_project(request, project_slug):
    project = None
    if project_slug:
        project = get_object_or_404(Project, name=project_slug) # somehow get your project object  

    qs = project.members.all()

    if request.method == 'POST':
        form = ProjectSettings(qs, request.POST)
        if form.is_valid(): # All validation rules pass
            # Process the data in form.cleaned_data
            project.summary = form.cleaned_data['summary']
            project.members = form.cleaned_data['members']
            project.save()
            return HttpResponseRedirect('/projects/' + project.slug + '/')
    else:
        form = ProjectSettings(qs)

    return render_to_response('update_project.html', {'form': form}, context_instance=RequestContext(request))

Using a ModelForm makes sense here if you do indeed have your summary field in your Project model.

forms.py:

class ProjectSettings(forms.ModelForm):
    def __init__(self, qs=None, *args, **kwargs):
        super(ProjectSettings, self).__init__(*args, **kwargs)
        self.fields['members'].widget = forms.CheckboxSelectMultiple()
    class Meta:
        model = Project
        fields = ('summary', 'members')

views.py:

def update_project(request, project_slug):
    project = None
    if project_slug:
        project = get_object_or_404(Project, name=project_slug) # somehow get your project object  

    if request.method == 'POST':
        form = ProjectSettings(request.POST, instance=project)
        if form.is_valid(): # All validation rules pass
            # Process the data in form.cleaned_data
            project.save()
            return HttpResponseRedirect('/projects/' + project.slug + '/')
    else:
        form = ProjectSettings(instance=project)

    return render_to_response('update_project.html', {'form': form}, context_instance=RequestContext(request))

这篇关于django表单和ModelMultipleChoiceField处理现有记录时的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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