Symfony2 $ user-> setPassword()将密码更新为纯文本[DataFixtures + FOSUserBundle] [英] Symfony2 $user->setPassword() updates password as plain text [DataFixtures + FOSUserBundle]
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问题描述
我的DataFixture类:
// Acme / SecurityBundle / DataFixtures / ORM / LoadUserData.php
<?php
命名空间Acme\SecurityBundle\DataFixtures\ORM;
使用Doctrine\Common\DataFixtures\FixtureInterface;
使用Doctrine\Common\Persistence\ObjectManager;
使用Acme\SecurityBundle\Entity\User;
class LoadUserData实现FixtureInterface
{
public function load(ObjectManager $ manager)
{
$ userAdmin = new User();
$ userAdmin-> setUsername('System');
$ userAdmin-> setEmail(isystem@example.com');
$ userAdmin-> setPassword('test');
$ manager-> persist($ userAdmin);
$ manager-> flush();
}
}
相关数据库输出:
id用户名电子邮件密码
pre>
1系统system@example.com 3f92m2tqa2kg8cookg84s4sow80880g测试
解决方案由于您使用的是FOSUserBundle,您可以使用
UserManager
做这个。我会使用这个代码(假设你有$ this-> container
set):code> public function load(ObjectManager $ manager)
{
$ userManager = $ this-> container-> get('fos_user.user_manager');
$ userAdmin = $ userManager-> createUser();
$ userAdmin-> setUsername('System');
$ userAdmin-> setEmail(isystem@example.com');
$ userAdmin-> setPlainPassword('test');
$ userAdmin-> setEnabled(true);
$ userManager-> updateUser($ userAdmin,true);
}
I'm trying to pre-populate a database with some User objects, but when I call
$user->setPassword('some-password');
and then save the user object, the string 'some-password' is stored directly in the database, instead of the hashed+salted password.My DataFixture class:
// Acme/SecurityBundle/DataFixtures/ORM/LoadUserData.php <?php namespace Acme\SecurityBundle\DataFixtures\ORM; use Doctrine\Common\DataFixtures\FixtureInterface; use Doctrine\Common\Persistence\ObjectManager; use Acme\SecurityBundle\Entity\User; class LoadUserData implements FixtureInterface { public function load(ObjectManager $manager) { $userAdmin = new User(); $userAdmin->setUsername('System'); $userAdmin->setEmail('system@example.com'); $userAdmin->setPassword('test'); $manager->persist($userAdmin); $manager->flush(); } }
And the relevant database output:
id username email salt password 1 System system@example.com 3f92m2tqa2kg8cookg84s4sow80880g test
解决方案Since you are using FOSUserBundle, you can use
UserManager
to do this. I would use this code (assuming you have$this->container
set):public function load(ObjectManager $manager) { $userManager = $this->container->get('fos_user.user_manager'); $userAdmin = $userManager->createUser(); $userAdmin->setUsername('System'); $userAdmin->setEmail('system@example.com'); $userAdmin->setPlainPassword('test'); $userAdmin->setEnabled(true); $userManager->updateUser($userAdmin, true); }
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