如何创建一个原则实体的模拟对象？ [英] How to create a mock object of a doctrine entity?

问题描述

我试图用phpunit编写一个使用原则2的模型的单元测试。我想嘲笑原则实体，但我真的不知道如何做这个。任何人都可以向我解释我需要做什么？我正在使用Zend Framework。

I'm trying to write a unit test with phpunit for a model that uses doctrine 2. I want to mock the doctrine entities but I really don't have a clue of how to do this. Can anyone explain to me how I need to do this? I'm using Zend Framework.

需要测试的模型

class Country extends App_Model
{
    public function findById($id)
    {
        try {
            return $this->_em->find('Entities\Country', $id);
        } catch (\Doctrine\ORM\ORMException $e) {
            return NULL;
        }
    }

    public function findByIso($iso)
    {
        try {
            return $this->_em->getRepository('Entities\Country')->findOneByIso($iso);
        } catch (\Doctrine\ORM\ORMException $e) {
            return NULL;
        }
    }
}

Bootstrap.php

protected function _initDoctrine()
{
    Some configuration of doctrine
    ... 
    // Create EntityManager
    $em = EntityManager::create($connectionOptions, $dcConf);
    Zend_Registry::set('EntityManager', $em);
}

扩展模型

class App_Model
{
    // Doctrine 2.0 entity manager
    protected $_em;

    public function __construct()
    {
        $this->_em = Zend_Registry::get('EntityManager');
    }
}

推荐答案

2实体应该像任何老类一样对待。您可以像PHPUnit中的任何其他对象一样模拟它们。

Doctrine 2 Entities should be treated like any old class. You can mock them just like any other object in PHPUnit.

$mockCountry = $this->getMock('Country');

正如@beberlei所说，你在Entity类里面使用EntityManager，它创建了一个粘性问题，打败了教义2的主要宗旨之一，即实体不关心自己的坚持。这些查找方法确实属于存储库类。

As @beberlei noted, you are using the EntityManager inside the Entity class itself, which creates a number of sticky problems, and defeats one of the major purposes of Doctrine 2, which is that Entity's aren't concerned with their own persistance. Those 'find' methods really belong in a repository class.

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