如何通过PHP从内容中找到一个URL？ [英] How to find a URL from a content by PHP?

问题描述

需要一个简单的preg_match，它会在内容中找到c.aspx（没有引号），如果它发现，它将返回整个url。作为示例

need a simply preg_match, which will find "c.aspx" (without quotes) in the content if it finds, it will return the whole url. As a example

$content = '<div>[4]<a href="/m/c.aspx?mt=01_9310ba801f1255e02e411d8a7ed53ef95235165ee4fb0226f9644d439c11039f%7c8acc31aea5ad3998&amp;n=783622212">New message</a><br/>';

现在，它应该从$ content preg_matchc.aspx，并将输出为

now it should preg_match "c.aspx" from $content and will give a output as

"/m/c.aspx?mt=01_9310ba801f1255e02e411d8a7ed53ef95235165ee4fb0226f9644d439c11039f%7c8acc31aea5ad3998&n=783622212"

$内容应该有更多的链接，除了c.aspx。我不想要他们我只想要所有具有c.aspx的网址。

The $content should have more links except "c.aspx". I don't want them. I only want all url that have "c.aspx".

请让我知道我该怎么做。

Please let me know how I can do it.

推荐答案

您可以使用DOM来解析HTML，而不是正则表达式。您可以使用正则表达式来解析属性值。

You use DOM to parse HTML, not regex. You can use regex to parse the attribute value though.

编辑：更新的示例，以便检查c.aspx。

updated example so it checks for c.aspx.

$content = '<div>[4]<a href="/m/c.aspx?mt=01_9310ba801f1255e02e411d8a7ed53ef95235165ee4fb0226f9644d439c11039f%7c8acc31aea5ad3998&amp;n=783622212">New message</a>

<a href="#bar">foo</a>

<br/>';

$dom = new DOMDocument();
$dom->loadHTML($content);

$anchors = $dom->getElementsByTagName('a');

if ( count($anchors->length) > 0 ) {
    foreach ( $anchors as $anchor ) {
        if ( $anchor->hasAttribute('href') ) {
            $link = $anchor->getAttribute('href');
            if ( strpos( $link, 'c.aspx') ) {
                echo $link;
            }
        }
    }
}

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