通过php和regex从文本字符串中找到URL? [英] Finding urls from text string via php and regex?

问题描述

我知道问题标题看起来很重复.但是我在这里找不到一些解决方案.

I know the question title looks very repetitive. But some of the solution i did not find here.

我需要从文本字符串中找到网址:

$pattern = '`.*?((http|https)://[\w#$&+,\/:;=?@.-]+)[^\w#$&+,\/:;=?@.-]*?`i';

    if (preg_match_all($pattern,$url_string,$matches)) {
        print_r($matches[1]);
    }

使用这种模式，我能够找到http://和https://的网址，这很不错.但是我有用户输入，人们在其中添加www.domain.com甚至domain.com

using this pattern i was able to find urls with http:// and https:// which is okey. But i have user input where people add url like www.domain.com even domain.com

因此，我需要先验证字符串，然后才能在其之前用通用协议http://替换www.domain.com domain.com.还是我需要提出更多好的模式?

So, i need to validate the string first where i can replace www.domain.com domain.com with common protocol http:// before them. Or i need to comeup with more good pattern?

我对正则表达式不好，也不知道该怎么办.

I am not good with regex and don't know what to do.

我的想法是先用http://和https://查找网址，然后将它们放入数组，然后用文本字符串中的space(")替换这些网址，然后使用其他模式它.但我不确定要使用哪种模式.

My idea is first finding the urls with http:// and https:// the put them in an array then replace these url with space(" ") in the text string then use other patterns for it. But i am not sure what pattern to use.

我正在使用此$url_string = preg_replace($pattern, ' ', $url_string );，但是如果两个http://或https://

I am using this $url_string = preg_replace($pattern, ' ', $url_string ); but that removes if any www.domain.com or domain.com url between two valid url with http:// or https://

如果您能提供帮助，那将是很好的.

If you can help that will be great.

要使事情更清楚:

我需要一种模式或某种其他方法，可以在其中找到文本字符串中的所有网址.网址示例为:

i need a pattern or some other method where i can find all urls in a text sting. the example of url are:

1. domain.com
2. www.domain.com
3. http://www.domain.com
4. http://domain.com
5. https://www.domain.com
6. https://domain.com

1. domain.com
2. www.domain.com
3. http://www.domain.com
4. http://domain.com
5. https://www.domain.com
6. https://domain.com

谢谢！ 5.

推荐答案

$pattern = '#(www\.|https?://)?[a-z0-9]+\.[a-z0-9]{2,4}\S*#i';
preg_match_all($pattern, $str, $matches, PREG_PATTERN_ORDER);

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