摆脱数组中的双引号,而不用将数组转换成字符串 [英] Getting rid of double quotes inside array without turing array into a string
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问题描述
我有一个数组
x = [1,2,3,:*, :+,4,5,: - ,:/]
x=["1", "2", "3", ":*", ":+", "4", "5", ":-", ":/"]
摆脱数组内的双引号。
I'm trying to get rid of the double quotation inside of the array.
我知道我可以使用:
x.to_s.gsub(' ','')
x.to_s.gsub('"','')
,它将输出一个字符串:
and it will output a string:
[1,2,3,:*,:+,4,5,...,,/]
"[1, 2, 3, :*, :+, 4, 5, :-, :/]"
我想要的输出是不是字符串的数组:
The desired output I want is an array not a string:
[1,2,3,... * :+,4,5,... - ,:/]
[1, 2, 3, :*, :+, 4, 5, :-, :/]
有没有办法摆脱双引号数组的每个元素,但仍然将数组作为数组?
Is there a way for me to get rid of the double quotes for each element of the array but still leave my array as an array?
提前感谢
推荐答案
eval x.to_s.gsub('"', '')
# => [1, 2, 3, :*, :+, 4, 5, :-, :/]
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