格式为双倍至8位小数 [英] format a double to 8 decimal places

问题描述

我有一个方法，我想以8 dp的双倍返回。

I have a method that i want to return as a double with 8 dp.

所以我有一个值从一个sp回来，在代码我是简单地做一个

so i have a value coming back from a sp and in the code i am simply doing

CheckSum = double.Parse(cmd.ExecuteScalar().ToString());

但是，如果sp返回这个：1541338.2349537
返回的double只有那些7dp，当我想要把尾随零。
喜欢这个.. 1541338.23495370

however, if the sp returns this :1541338.2349537 the returned double only has those 7dp, when i would like it to put a trailing zero on. like this.. 1541338.23495370

我无法找到一个方法来双重格式化 - 即强制它为8dp，而不是返回格式化的字符串。
我不想做。
可以有人解释：）

i cant find a method on the double to format it - ie force it to 8dp, other than to return a formatted string. which i dont want to do. can someone explain please :)

谢谢

nat

推荐答案

double d = 0.123456789;
string sDisplayValue = d.ToString("0.00000000");

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