无法输出多维数组 [英] Cannot output multi-dimensional array

问题描述

我无法从多维数组中获取任何输出。我想使用push_array方法获取我的数据。

I cannot get any output from my multi-dimensional array. I'm trying to get my data using the push_array method.

我想得到我的输出：

• John，1001


• Tom，1002


• Jerry，1003


• Sarah，1004

• John, 1001
• Tom, 1002
• Jerry, 1003
• Sarah, 1004

但是，我没有得到任何输出。我知道数组正在工作，当我回显$ message并且不在我的输出foreach数组中使用$ id和$ name时，我得到以下输出。

However, I'm not getting any output. I know the array is working though as I get the following output when I echo $message and do not use $id and $name in my output foreach array.

当前输出：（当回显$ message时）

Current output: (when echoing $message)

• 1


• 2


• 3


• 4

• 1
• 2
• 3
• 4

但是当我使用$ id和$ name这里显示的时候没有显示。

But nothing gets shown when I use $id and $name as shown here.

<ul class="result"><?php
    foreach ($output as $message) {
        $id = $message[1][0];
        $name = $message[1][1];
    ?><li>
        <a href="handleDownload.php?id=<?php echo $id;?>"><?php echo $name; ?>      </a>
    </li><php } ?>
</ul>

这是我的完整代码：

<?php 
$Download = new Download();
$result = array(); //store results of upload
try {
    $Download->showDBFiles();
    $output = $Download->getMessages();
} catch (Exception $e) {
    $result[] = $e->getMessage();
}

?>

<h2>Output</h2>
<?php if ($output) { ?>
    <ul class="result">
    <?php  foreach ($output as $message) {
        $id = $message[1][0];
        $name = $message[1][1];
    ?>
        <li><a href="handleDownload.php?id=<?php echo $id;?>"><?php echo $name; ?></a></li>
<?php } ?>
</ul>
<?php } ?>

定义数组的功能

protected $messages = array();

        public function showDBFiles() {
            global $database;
            $values=array();
            $sql = "SELECT resume_id, resume_title FROM ".self::$table_name;
            $result = $database->query($sql);
            if(mysqli_num_rows($result)==0){
                 $this->messages[] = "Database is empty";
            }else{
                while(list($id, $name) = mysqli_fetch_array($result)){
                    array_push($this->messages, array($id, $name));
                }
            }
        }

        public function getMessages()
        {
                return $this->messages;
        }

更新：
使用jedrzej.kurylo的建议后，我可以拥有$ id和$ name值，如我的var_dump输出所示：

UPDATE: After using the suggestion by jedrzej.kurylo I'm able to have the $id and $name values as shown in my var_dump output:

array（4）{[0] => array（2）{[0 ] => string（2）73[1] => string（2）qd} [1] => array（2）{[0] => string（2）72[1] => string（3）jav} [2] => array（2）{[0] => string（2）70[1] => string（4）da12 2）{[0] => string（2）71[1] => string（3）jav}}

array(4) { [0]=> array(2) { [0]=> string(2) "73" [1]=> string(2) "qd" } [1]=> array(2) { [0]=> string(2) "72" [1]=> string(3) "jav" } [2]=> array(2) { [0]=> string(2) "70" [1]=> string(4) "da12" } [3]=> array(2) { [0]=> string(2) "71" [1]=> string(3) "jav" } }

现在我不确定我的输出是这样的：

However for some reason that I'm unsure of my output is now this:

• d


• a


• a


• a

• d
• a
• a
• a

推荐答案

p>问题在于如何在这里使用 array_push ：

The problem is with how you use array_push here:

$this->messages[] = array_push($values, array($id, $name));

array_push 不返回更新的数组，但新的数量项阵列 - 请参阅 http://php.net/manual/en/function.array- push.php 。这就是为什么你的输出中整数增加。

array_push does not return updated array but the new number of items in the array - see http://php.net/manual/en/function.array-push.php. That's why you're getting increasing integers in your output.

请改为：

while(list($id, $name) = mysqli_fetch_array($result)){
  array_push($this->messages, array($id, $name));
}

或只是

while(list($id, $name) = mysqli_fetch_array($result)){
  $this->messages[] = array('id'=>$id, 'name'=>$name);
}

然后，您可以访问 $ id 和 $ name 如下：

Then you can access $id and $name like this:

$id = $message['id'];
$name = $message['name'];

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