无法删除重复的行 [英] Can't Remove Duplicate Rows
问题描述
每个记录最多可以有40个不同的 person_user.description 字段。问题是，我收到重复的行，因为记录有多个描述条目。你可以帮我把这些额外的副本放在同一个记录行上，如：
Each record could have up to 40 different person_user.description fields. Problem is, I am getting duplicate rows because records have multiple description entries. Can you help me put those additional duplicates on the same record row like:
| 1 | badge.bid | person.first_name | person。姓氏| person.type | 1 | 2 | 3 | 4 | 5 |等| 40 |
| 2 | badge.bid | person.first_name | person.last_name | person.type | 1 | 2 | 3 | 4 | 5 | etc | 40 |
| 3 | badge.bid | person.first_name | person.last_name | person.type | 1 | 2 | 3 | 4 | 5 | etc | 40 |
|1|badge.bid|person.first_name|person.last_name|person.type|1|2|3|4|5|etc|40| |2|badge.bid|person.first_name|person.last_name|person.type|1|2|3|4|5|etc|40| |3|badge.bid|person.first_name|person.last_name|person.type|1|2|3|4|5|etc|40|
而不是这样：
| 1 | badge.bid | person.first_name | person.last_name | person.type | person_user.description |
| 1 | badge.bid | person.first_name | person.last_name | person.type | person_user.description |
| 2 | badge.bid | person.first_name | person.last_name | person.type | person_user.description |
| 2 | badge.bid | person.first_name | person.last_name | person.type | person_user.description |
|1|badge.bid|person.first_name|person.last_name|person.type|person_user.description| |1|badge.bid|person.first_name|person.last_name|person.type|person_user.description| |2|badge.bid|person.first_name|person.last_name|person.type|person_user.description| |2|badge.bid|person.first_name|person.last_name|person.type|person_user.description|
SELECT person.id,
badge.bid,
person.first_name,
person.last_name,
person.type,
person_user.description
FROM person,
badge,
person_user
WHERE person.id = badge.id
AND person.id = person_user.person_id
AND badge.bid NOT LIKE "111%"
AND badge.access_date >= 20130401
GROUP BY person.id,
badge.bid,
person.first_name,
person.last_name,
person.type,
person_user.description
ORDER BY person.id
推荐答案
得出结论。这是我如何实现的。
Got it figured out. Here is how I achieved it by the way.
SELECT P.id,
B.bid,
P.first_name,
P.last_name,
PT.description,
PU1.description PU1,
PU2.description PU2,
PU3.description PU3,
PU4.description PU4,
PU5.description PU5,
PU6.description PU6,
PU7.description PU7,
PU8.description PU8,
PU9.description PU9,
PU10.description PU10,
PU11.description PU11,
PU12.description PU12,
PU13.description PU13,
PU14.description PU14,
PU15.description PU15,
PU16.description PU16,
PU17.description PU17,
PU18.description PU18,
PU19.description PU19,
PU20.description PU20,
PU21.description PU21,
PU22.description PU22,
PU23.description PU23,
PU24.description PU24,
PU25.description PU25,
PU26.description PU26,
PU27.description PU27,
PU28.description PU28,
PU29.description PU29,
PU30.description PU30,
PU31.description PU31,
PU32.description PU32,
PU33.description PU33,
PU34.description PU34,
PU35.description PU35,
PU36.description PU36,
PU37.description PU37,
PU38.description PU38,
PU39.description PU39,
PU40.description PU40
FROM person P,
OUTER badge B,
person_type PT,
OUTER person_user PU1,
OUTER person_user PU2,
OUTER person_user PU3,
OUTER person_user PU4,
OUTER person_user PU5,
OUTER person_user PU6,
OUTER person_user PU7,
OUTER person_user PU8,
OUTER person_user PU9,
OUTER person_user PU10,
OUTER person_user PU11,
OUTER person_user PU12,
OUTER person_user PU13,
OUTER person_user PU14,
OUTER person_user PU15,
OUTER person_user PU16,
OUTER person_user PU17,
OUTER person_user PU18,
OUTER person_user PU19,
OUTER person_user PU20,
OUTER person_user PU21,
OUTER person_user PU22,
OUTER person_user PU23,
OUTER person_user PU24,
OUTER person_user PU25,
OUTER person_user PU26,
OUTER person_user PU27,
OUTER person_user PU28,
OUTER person_user PU29,
OUTER person_user PU30,
OUTER person_user PU31,
OUTER person_user PU32,
OUTER person_user PU33,
OUTER person_user PU34,
OUTER person_user PU35,
OUTER person_user PU36,
OUTER person_user PU37,
OUTER person_user PU38,
OUTER person_user PU39,
OUTER person_user PU40
WHERE P.id=B.person_id
AND P.type=PT.id
AND (P.id=PU1.person_id
AND PU1.slot_number=1)
AND (P.id=PU2.person_id
AND PU2.slot_number=2)
AND (P.id=PU3.person_id
AND PU3.slot_number=3)
AND (P.id=PU4.person_id
AND PU4.slot_number=4)
AND (P.id=PU5.person_id
AND PU5.slot_number=5)
AND (P.id=PU6.person_id
AND PU6.slot_number=6)
AND (P.id=PU7.person_id
AND PU7.slot_number=7)
AND (P.id=PU8.person_id
AND PU8.slot_number=8)
AND (P.id=PU9.person_id
AND PU9.slot_number=9)
AND (P.id=PU10.person_id
AND PU10.slot_number=10)
AND (P.id=PU11.person_id
AND PU11.slot_number=11)
AND (P.id=PU12.person_id
AND PU12.slot_number=12)
AND (P.id=PU13.person_id
AND PU13.slot_number=13)
AND (P.id=PU14.person_id
AND PU14.slot_number=14)
AND (P.id=PU15.person_id
AND PU15.slot_number=15)
AND (P.id=PU16.person_id
AND PU16.slot_number=16)
AND (P.id=PU17.person_id
AND PU17.slot_number=17)
AND (P.id=PU18.person_id
AND PU18.slot_number=18)
AND (P.id=PU19.person_id
AND PU19.slot_number=19)
AND (P.id=PU20.person_id
AND PU20.slot_number=20)
AND (P.id=PU21.person_id
AND PU21.slot_number=21)
AND (P.id=PU22.person_id
AND PU22.slot_number=22)
AND (P.id=PU23.person_id
AND PU23.slot_number=23)
AND (P.id=PU24.person_id
AND PU24.slot_number=24)
AND (P.id=PU25.person_id
AND PU25.slot_number=25)
AND (P.id=PU26.person_id
AND PU26.slot_number=26)
AND (P.id=PU27.person_id
AND PU27.slot_number=27)
AND (P.id=PU28.person_id
AND PU28.slot_number=28)
AND (P.id=PU29.person_id
AND PU29.slot_number=29)
AND (P.id=PU30.person_id
AND PU30.slot_number=30)
AND (P.id=PU31.person_id
AND PU31.slot_number=31)
AND (P.id=PU32.person_id
AND PU32.slot_number=32)
AND (P.id=PU33.person_id
AND PU33.slot_number=33)
AND (P.id=PU34.person_id
AND PU34.slot_number=34)
AND (P.id=PU35.person_id
AND PU35.slot_number=35)
AND (P.id=PU36.person_id
AND PU36.slot_number=36)
AND (P.id=PU37.person_id
AND PU37.slot_number=37)
AND (P.id=PU38.person_id
AND PU38.slot_number=38)
AND (P.id=PU39.person_id
AND PU39.slot_number=39)
AND (P.id=PU40.person_id
AND PU40.slot_number=40)
AND B.status=0
AND B.bid NOT LIKE "111%"
AND B.access_date>=20130401
ORDER BY P.id,
P.last_name
这篇关于无法删除重复的行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
