自我复制程序 [英] Self-reproducing program

问题描述

编写一个自我重现程序。这样的程序是没有输入的程序，运行时，在标准输出流中写入自己的源文本的副本。

我的解决方案：

  using std :: string; 
使用std :: cout; 
使用std :: endl; 
使用std :: ifstream; 
使用std :: getline; 
 
 void selfReproduce16_1（）
 {
 ifstream thisFile（C：\\Users\\Kevin\\\Documents\\NetBeansProjects\\\ \\ Accelerated_C ++ _ Exercises\\\Chapter_16.cpp，ifstream :: in）; 
 
 string curline; 
 
 bool foundHeader = false; 
 
 while（getline（thisFile，curLine））
 {
 if（！curLine.compare（void selfReproduce16_1（））|| foundHeader）
 {
 foundHeader = true; 
 cout<<< curline<< ENDL; 
} 
 
} 
 
} 
  

这只打印出解决方案的源文本（此函数）。这是他们想到的解决方案吗？

我想要一个动态解决方案，不需要硬编码源文件的位置。但是，我不知道在运行时自动获取源文件的位置的方法。

与此相关的另一点是包含包含文件，（当遇到函数调用时），自动获取该函数的源文件的位置对我来说，这将是一个真正的自我复制程序。

这是否可能在C ++中？如果是这样，那么怎么样？

解决方案

打印自己的程序称为 Quine 。

我认为你的解决方案不被认为是有效的：不允许读取文件（也不得到任何其他类型的输入）。可以写一个Quine C ++程序， here 你可以在几个例子中找到很多的quine实现语言。

I am questioning my solution to the last exercise in Accelerated C++:

Write a self-reproducing program. Such a program is one that does no input, and that, when run, writes a copy of its own source text on the standard output stream.

My solution:

using std::string;
using std::cout;
using std::endl;
using std::ifstream;
using std::getline;

void selfReproduce16_1()
{
    ifstream thisFile("C:\\Users\\Kevin\\Documents\\NetBeansProjects\\Accelerated_C++_Exercises\\Chapter_16.cpp", ifstream::in);

    string curLine;

    bool foundHeader = false;

    while(getline(thisFile, curLine))
    {
        if(!curLine.compare("void selfReproduce16_1()") || foundHeader)
        {
            foundHeader = true;
            cout << curLine << endl;
        }

    }

}

This only prints out the source text of the solution (this function). Is this the solution that they had in mind?

I would like a dynamic solution that does not require hard-coding the location of the source file. However, I am not aware of a way to get the location of a source file automatically during runtime.

Another point related to that is the inclusion of "included" files, and (when encountering a function call), automatically obtaining the location of the source file that the function is stored in. To me, this would be a true "self-reproducing" program.

Is this possible in C++? If so, how?

解决方案

A program that prints itself is called Quine.

I think your solution wouldn't be considered valid: quines usually aren't allowed to read files (nor to get any other kind of input). It's possible to writ a Quine C++ program, here you could find many quine implementations in several languages.

这篇关于自我复制程序的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！