C ++中动态分配内存的初始值 [英] Initial Value of Dynamically-Allocated Memory in C++

问题描述

在C ++中，当您动态分配 int 的数组时，是 int 未定义的值初始化为0？

In C++, when you dynamically allocate an array of int, are the values of the ints undefined or initialized to 0?

    int *array = new int[50];

推荐答案

该术语是未初始化 。但它取决于如何初始化数组。您可以将其初始化为：

The term is uninitialized. But it depends how you initialize the array. You could value-initialize it:

int *array = new int[50]();

，值为0。

如果您将其初始化，您将无法知道有什么值，因为从它们的阅读将是未定义的行为。

If you leave it uninitialized, you can't know what values are there because reading from them would be undefined behavior.

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