使用Maven pom.xml将战争文件部署到Tomcat根目录 [英] Deploying a War File to Tomcat Root With Maven pom.xml

问题描述

假设以下 pom.xml maven将构建一个 client.war 文件，当Tomcat部署到网址 www.server.com:8080/client /

需要更改哪些应用程序才能在服务器根目录下可达到 www.server.com:8080 / ？

 <项目> 
< modelVersion> 4.0.0< / modelVersion> 
< groupId> ...< / groupId> 
< artifactId>客户端< / artifactId> 
< packaging> war< / packaging> 
< version> 1.0-SNAPSHOT< / version> 
< name> ...< / name> 
< url> http：//maven.apache.org< / url> 
< build> 
< resources> 
< resource> 
< directory> target / generated-resources< / directory> 
< / resource> 
< resource> 
< directory> src / main / resources< / directory> 
< filtering> true< / filtering> 
< / resource> 
< / resources> 
< plugins> 
 ... 
< / plugins> 
< finalName> client< / finalName> 
< / build> 
 ... 
< / project> 
  

解决方案

我相信你如果你愿意，可以离开名为client.war的战争。然后配置 tomcat6插件，设置路径如下：

 < plugin> 
< groupId> org.apache.tomcat.maven< / groupId> 
< artifactId> tomcat6-maven-plugin< / artifactId> 
< version> 2.0-beta-1< / version> 
<！ - 将配置放在执行中，如果你想...  - > 
< configuration> 
< path> /< / path> 
< warFile> $ {project.build.directory} /client.war</warFile> 
<！ - 其他配置选项 - > 
< / configuration> 
< / plugin> 
  

我没有使用tomcat7版本的插件，但我猜这是类似的。 p>

Assuming the following pom.xml maven would build a client.war file which when deployed to Tomcat will have the URL www.server.com:8080/client/

What would one have to change so the application can be reached at the server root www.server.com:8080/?

<project>
    <modelVersion>4.0.0</modelVersion>
    <groupId>...</groupId>
    <artifactId>client</artifactId>
    <packaging>war</packaging>
    <version>1.0-SNAPSHOT</version>
    <name>...</name>
    <url>http://maven.apache.org</url>
    <build>
        <resources>
            <resource>
                <directory>target/generated-resources</directory>
            </resource>
            <resource>
                <directory>src/main/resources</directory>
                <filtering>true</filtering>
            </resource>
        </resources>
        <plugins>
            ...
        </plugins>
        <finalName>client</finalName>
    </build>
...
</project>

解决方案

I believe you can leave the war named client.war if you'd like. Then configure the tomcat6 plugin, setting the path like this:

<plugin>
  <groupId>org.apache.tomcat.maven</groupId>
  <artifactId>tomcat6-maven-plugin</artifactId>
  <version>2.0-beta-1</version>
      <!-- put the configuration in an execution if you want to... -->
      <configuration>
        <path>/</path>
        <warFile>${project.build.directory}/client.war</warFile>
        <!-- other config options here -->
      </configuration>
</plugin>

I haven't used tomcat7 version of the plugin, but I'm guessing it's similar.

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