如何迭代发生器函数的结果 [英] How to iterate over the results of a generator function

问题描述

有没有更好的方法来迭代发生器的结果，我的for循环是丑陋的：

  for（let job = readyJob.next（）;！job.done; job = readyJob.next（））{} 
  

在上下文中有一个生成函数可以确定是否有一批工作，由1 .. *作业组成（生成器也可能不返回批处理中的作业）。有一个连续的循环来实例化生成器，并在批处理中进行重复操作（日志记录）。

这个迭代问题有一个更优雅的解决方案。我的意思是这看起来像Java / C＃的传统迭代器，这不错。像每个这样的东西将是超级可读的...这是我的希望无论如何。

  let getReadyJob = function *（instance） {
 let numJobs = 7; // getRandomInt（0，10）; 
 for（let i = 0; i< numJobs; i ++）{
 yield {
 jobId：''+ instance +'::'+ i，
 jobReadyOn new Date（））。valueOf（）
}; 
} 
} 
  

然后

$ b $（$）$（$）$（$）$（$）$（$）$ {
let readyJob = getReadyJob（）

for（let job = readyJob.next .done; job = readyJob.next（））{
console.log（JSON.stringify（job.value））;
}
}

解决方案

是如果您的环境已经支持 的：

  for（var job of readyJob）{
 // ... 
} 
  

如果没有，看过这几次：

  var next; 
 while（！（next = readyJob.next（））。done）{
 var job = next.value; 
 // ... 
} 
  




Is there a better way to iterate over the results of a generator, my for loop is ugly:

for(let job = readyJob.next(); !job.done; job = readyJob.next()){ } 

In context there is a generator function that can determine if there is a batch of work, consisting of 1..* jobs (the generator may also return no jobs in the batch). There is a continuous loop that instantiates the generator and iterates over the batch doing work on the job (logging).

Is there a more elegant solution to this iteration problem. I mean this looks like a traditional iterator from Java/C# which isn't bad. Something like an "each" would be super readable... That's my hope anyhow.

 let getReadyJob = function *(instance){
    let numJobs = 7 ; // getRandomInt(0, 10) ;
    for(let i = 0; i < numJobs; i++) {
        yield {
            jobId: '' + instance + '::' + i,
            jobReadyOn: (new Date()).valueOf()
        };
    }
}

then

while(true){
    let readyJob = getReadyJob()

    for(let job = readyJob.next(); !job.done; job = readyJob.next()){
        console.log(JSON.stringify(job.value)) ;
    }
}

解决方案

Yes, if your environment already supports for...of:

for (var job of readyJob) {
  // ...
}

If not, have seen this a couple of times:

var next;
while (!(next = readyJob.next()).done) {
   var job = next.value;
   // ...
}

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