如何在Elasticsearch中将两个查询的分数相加在一起？ [英] How can I multiply the score of two queries together in Elasticsearch?

问题描述

在Solr中，我可以使用查询函数查询返回查询的数值分数，我可以在 bf的上下文中使用用户参数类似 bf = product（query（'cat'），query（'dog'））将两个相关性分数相乘。 p>

Elasticsearch具有通常更灵活的搜索API，但我无法弄清楚我将如何完成同样的壮举。我可以在function_query的script_function中使用 _score ，但我只能使用主查询的 _score 。如何整合另一个查询的分数？您可以使用脚本编写一个TF * IDF评分函数，如何将分数乘以一起？

解决方案

function_score 查询。这样（忽略Lucene的查询和长度规范化）：

 script：tf = _index [field] [term] .tf（）; idf =（1 + log（_index.numDocs（）/（_index [field] [term] .df（）+ 1）））; return sqrt（tf）* pow（idf，2） b $ b  

您将使用猫和狗的功能结果的产品，并将其添加到您的原始查询分数。

以下是完整的查询 gist 。

In Solr I can use the query function query to return a numerical score for a query and I can user that in the context of a bf parameter something like bf=product(query('cat'),query('dog')) to multiply two relevance scores together.

Elasticsearch has search API that is generally more flexible to work with, but I can't figure out how I would accomplish the same feat. I can use _score in a script_function of a function_query but I can only user the _score of the main query. How can I incorporate the score of another query? How can I multiply the scores together?

解决方案

You could script a TF*IDF scoring function using a function_score query. Something like this (ignoring Lucene's query and length normalization):

"script": "tf = _index[field][term].tf(); idf = (1 + log ( _index.numDocs() / (_index[field][term].df() + 1))); return sqrt(tf) * pow(idf,2)"

You'd take the product of those function results for 'cat' and 'dog' and add them to your original query score.

Here's the full query gist.

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