Vim - 通过正则表达式搜索和替换来增量编号 [英] Vim - incremental numbering via regular expression search and replace

问题描述

我有这个代码：

  array（'id'=> 1，'name'=& ，'date_of_birth'=>2014-10-31，breed_id=> 1），
 array（'id'=> 1，'name'=>Jurka date_of_birth'=>2014-11-31，breed_id=> 2），
 array（'id'=> 1，'name'=>Nyash，'date_of_birth'= >2014-12-31，breed_id=> 3），
 array（'id'=> 1，'name'=>Meowy，'date_of_birth'=& 2014-01-31，breed_id=> 4），
 array（'id'=> 1，'name'=>Yummi，'date_of_birth'=>2014-10 -31，breed_id=> 2），
数组（'id'=> 1，'name'=>Barss，'date_of_birth'=>2014-05-31 ，breed_id=> 2），
 array（'id'=> 1，'name'=>Nonam，'date_of_birth'=>2014-05-31， => null 
  

我想要更改所有'id' => 1 （除了第1个），所以数字将增加b y 1.使用Emacs实现很简单：

  Mx replace-regexp 
 \（1，\） 
 \，（1+ \＃），
  

如上所述这里。经过一些研究，我使用Vim实现的最大限度是（从 here ）：

 ：let i = 1 | g / 1，/ s // \ = i / |让我+ = 1 
  

但是，这会删除所有以下逗号：

  array（'id'=> 1'name'=>Murka，'date_of_birth'=>2014-10-31， => 1），
 array（'id'=> 2'name'=>Jurka，'date_of_birth'=>2014-11-31，breed_id=> 2），
 array（'id'=> 3'name'=>Nyash，'date_of_birth'=>2014-12-31，breed_id=> 3），
数组（'id'=> 4'name'=>Meowy，'date_of_birth'=>2014-01-31，breed_id=> 4），
数组（'id'=> 5'name'=>Yummi，'date_of_birth'=>2014-10-31，breed_id=> 2），
 array（'id' => 6'name'=>Barss，'date_of_birth'=>2014-05-31，breed_id=> 2），
 array（'id'=> 'name'=>Nonam，'date_of_birth'=>2014-05-31，breed_id=> null），
  

所以我必须解决它（我知道这很容易）。 p>

我知道这个和宏我只想知道Vim中是否有单行命令解决方案。

更一般的问题是：Vim可能会注入一些逻辑，如条件语句，操纵正则表达式引用？ Emacs中的示例将是：

  CM-％\（^。* \）\（linear-渐变（\）\（to right\ | to bottom\）\（。* $ \）< RET> 
 \& Cq Cj 
 \1-prefix -\2\，（if（equal）to right\3）lefttop）\4 
  

这个一年前帮助我重构了一些巨大的可怕的HTML代码，内置了很多内联CSS。

解决方案

我没有回答你的一般问题，但是我有一个针对你的具体情况，你可以通过将逗号放在正面的前提下，使你的命令工作，如下所示： p>

 ：let i = 1 | g / 1（\，\）\ @ = / s // \ = i / | let i + = 1 
  

现在，它只会替换 1 。

I have this code:

array ('id' => 1, 'name' => "Murka", 'date_of_birth' => "2014-10-31", "breed_id" => 1),
array ('id' => 1, 'name' => "Jurka", 'date_of_birth' => "2014-11-31", "breed_id" => 2),
array ('id' => 1, 'name' => "Nyash", 'date_of_birth' => "2014-12-31", "breed_id" => 3),
array ('id' => 1, 'name' => "Meowy", 'date_of_birth' => "2014-01-31", "breed_id" => 4),
array ('id' => 1, 'name' => "Yummi", 'date_of_birth' => "2014-10-31", "breed_id" => 2),
array ('id' => 1, 'name' => "Barss", 'date_of_birth' => "2014-05-31", "breed_id" => 2),
array ('id' => 1, 'name' => "Nonam", 'date_of_birth' => "2014-05-31", "breed_id" => null

I'll want to change all 'id' => 1 (except the 1st) so the number will increment by 1. It's simple to achieve with Emacs:

M-x replace-regexp
\(1,\)
\,(1+ \#),

As described here. After some research the maximum that I've been able to achieve with Vim is (inspired from here):

:let i=1 | g/1,/ s//\=i/ | let i+=1

But this removes all the following commas:

array ('id' => 1 'name' => "Murka", 'date_of_birth' => "2014-10-31", "breed_id" => 1),
array ('id' => 2 'name' => "Jurka", 'date_of_birth' => "2014-11-31", "breed_id" => 2),
array ('id' => 3 'name' => "Nyash", 'date_of_birth' => "2014-12-31", "breed_id" => 3),
array ('id' => 4 'name' => "Meowy", 'date_of_birth' => "2014-01-31", "breed_id" => 4),
array ('id' => 5 'name' => "Yummi", 'date_of_birth' => "2014-10-31", "breed_id" => 2),
array ('id' => 6 'name' => "Barss", 'date_of_birth' => "2014-05-31", "breed_id" => 2),
array ('id' => 7 'name' => "Nonam", 'date_of_birth' => "2014-05-31", "breed_id" => null),

So I have to fix it (I know it's easy).

I am aware of this and macros, I'm just interested to know if there any one-line command solution in Vim.

More general question: is it possible in Vim to inject some logic like conditional statements, manipulating on regex back references? The example for this in Emacs would be:

C-M-% \(^.*\)\(linear-gradient(\)\(to right\|to bottom\)\(.*$\) <RET>
\& C-q C-j
\1-prefix-\2\,(if (equal "to right" \3) "left" "top")\4

This one helped me about a year+ ago to refactor some huge scary HTML code that had a much of inline CSS.

解决方案

I don't have an answer to your general question, but I do have one for your specific situation. You can make your command work by putting the comma into a positive look-ahead, like this:

:let i=1 | g/1(\,\)\@=/ s//\=i/ | let i+=1

Now it will only replace the 1.

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