Shell脚本解密并将文件从一个目录移动到另一个目录 [英] Shell script to decrypt and move files from one directory to another directory

问题描述

我有一个目录，它有几个文件。我试图解密这些文件并将它们移动到另一个目录。我不知道如何设置输出文件名并移动它。

所以，目录结构如下所示：

  /Applications/MAMP/bin/decryptandmove.sh 
 /Applications/MAMP/bin/passtext.txt 
 / Applications / MAMP / bin / encrypted / test1.txt.pgp 
 /Applications/MAMP/bin/encrypted/test2.txt.pgp 
 /应用程序/ MAMP / htdocs / www / decryptpted / 
  

对于在加密目录中找到的所有文件，我正在尝试解密它们，然后将它们移动到目录www / decryptpted /。我不知道加密目录中的文件名将提前（此脚本最终将通过cron作业运行），因此我只想输出具有相同文件名的解密文件，但不使用pgp。因此，结果将是：

  /Applications/MAMP/bin/decryptandmove.sh 
 / Applications / MAMP / bin / passtext.txt 
 /应用程序/ MAMP / bin / encrypted / 
 /Applications/MAMP/htdocs/decrypted/test1.txt.pgp 
 /应用程序/ MAMP / htdocs / decryptpted / test2 .txt.pgp 
  

所以，这是我迄今为止写的，它不工作。 FILE和FILENAME都错了。我甚至没有得到移动的部分。

  pass_phrase =`cat passtext.txt | awk'{print $ 1} '/应用程序/ MAMP / bin / encrypted /'中的文件
 
; 
 do 
 FILENAME = $（basename $ FILE .pgp）
 gpg --passphrase $ pass_phrase --output $ FILENAME --decrypt $ FILE 
 done 
  




解决方案

 ＃！/ bin / bash 
p = $（< passtext.txt）
 set  -  $ p 
 pass_phrase = $ 1 
 destination =/ Applications / MAMP / htdocs / www / decryptpted /
 cd / Applications / MAMP / bin / encrypted 
用于* .pgp中的FILE; 
 do 
 FILENAME = $ {FILE％.pgp} 
 gpg --passphrase$ pass_phrase - 输出$ destination / $ FILENAME--decrypt$ FILE
完成
  




I have a directory and in it has several files. I'm trying to decrypt those files and move them to another directory. I can't figure out how to set the output filename and move it.

So, the directory structure looks like the following:

/Applications/MAMP/bin/decryptandmove.sh
/Applications/MAMP/bin/passtext.txt
/Applications/MAMP/bin/encrypted/test1.txt.pgp
/Applications/MAMP/bin/encrypted/test2.txt.pgp
/Applications/MAMP/htdocs/www/decrypted/

For all the files that are found in the encrypted directory, I'm trying to decrypt them and then move them to the directory www/decrypted/. I don't know what the filenames in the encrypted directory will be ahead of time (this script will eventually run via cron job), so I wanted to just output the decrypted files with the same filenames, but without the pgp. So, the result would be:

/Applications/MAMP/bin/decryptandmove.sh
/Applications/MAMP/bin/passtext.txt
/Applications/MAMP/bin/encrypted/
/Applications/MAMP/htdocs/decrypted/test1.txt.pgp
/Applications/MAMP/htdocs/decrypted/test2.txt.pgp

So, this is all I have written so far and it doesn't work. FILE and FILENAME are both wrong. I haven't even gotten to the moving part.

pass_phrase=`cat passtext.txt|awk '{print $1}'`

for FILE in '/Applications/MAMP/bin/encrypted/';
 do
    FILENAME=$(basename $FILE .pgp) 
    gpg --passphrase $pass_phrase --output $FILENAME --decrypt $FILE
 done

解决方案

#!/bin/bash
p=$(<passtext.txt)
set -- $p
pass_phrase=$1
destination="/Applications/MAMP/htdocs/www/decrypted/"
cd /Applications/MAMP/bin/encrypted
for FILE in *.pgp;
do
    FILENAME=${FILE%.pgp}
    gpg --passphrase "$pass_phrase" --output "$destination/$FILENAME" --decrypt "$FILE"
done

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