类别范围的枚举 [英] Class-scoped enum
问题描述
boost :: python
来模仿,所以我可以写 MyClass python中的.value
boost :: python :: class _
没有一个枚举_
方法,我正在寻找解决方法。 > -
我第一次尝试使用lambdas,如
MyClass {
enum {value1,value2};
};
class_&MyClass>(MyClass)。add_property(value1,& [](){return value1;})staticmethod(value1);
这会给编译器错误(在
get_signature
add_property
)。我知道我可以为每个值创建getter方法,但对我来说似乎很尴尬(打字)。 -
使用
attr
:auto classObj = class_< MyClass>(MyClass);
classObj.attr(value1)=(int)value1;
classObj.attr(value2)=(int)value2;
但它不能像
.def
和/或其他方法返回参考实例。
有更优雅的解决方案吗?
您可以使用范围:
#include< boost / python / module.hpp>
#include< boost / python / class.hpp>
#include< boost / python / scope.hpp>
#include< boost / python / enum.hpp>
命名空间bp = boost :: python;
class MyClass {
public:
枚举MyEnum {value1,value2};
};
BOOST_PYTHON_MODULE(nestedtest){
bp :: scope the_scope
= bp :: class_< MyClass>(MyClass)
;
bp :: enum_< MyClass :: MyEnum>(MyEnum)
.value(value1,MyClass :: value1)
.value(value2 MyClass :: value2)
.export_values()
;
}
然后在python中,你的枚举值是:
在[8]中:nestedtest.MyClass.MyEnum.values
输出[8]:{0:nestedtest.MyEnum.value1,1:嵌套测试.MyEnum.value2}
在[9]中:nestedtest.MyClass.MyEnum.value1
输出[9]:nestedtest.MyEnum.value1
在[10 ]:nestedtest.MyClass.MyEnum.value2
Out [10]:nestedtest.MyEnum.value2
(从我的ipython shell,我测试了这个和所有;)
I have a c++ class with an enum inside, and I wanted to mimick that with boost::python
, so that I can write MyClass.value
in python. boost::python::class_
does not have an enum_
method, and I was looking for workarounds.
I first tried with lambdas like
MyClass{ enum{value1,value2}; }; class_<MyClass>("MyClass").add_property("value1",&[](){return value1;}).staticmethod("value1");
which gives compiler error (in
get_signature
foradd_property
). I know I could create getter method for each of the values, but that seems very awkward to me (typing-wise).Using
attr
:auto classObj=class_<MyClass>("MyClass"); classObj.attr("value1")=(int)value1; classObj.attr("value2")=(int)value2;
but it cannot be chained like
.def
and other methods returning reference to the instance.
Is there a more elegant solution?
You can do it using a scope:
#include <boost/python/module.hpp>
#include <boost/python/class.hpp>
#include <boost/python/scope.hpp>
#include <boost/python/enum.hpp>
namespace bp = boost::python;
class MyClass{
public:
enum MyEnum {value1,value2};
};
BOOST_PYTHON_MODULE(nestedtest){
bp::scope the_scope
= bp::class_<MyClass>("MyClass")
;
bp::enum_<MyClass::MyEnum>("MyEnum")
.value("value1", MyClass::value1)
.value("value2", MyClass::value2)
.export_values()
;
}
Then in python, your enum values are:
In [8]: nestedtest.MyClass.MyEnum.values
Out[8]: {0: nestedtest.MyEnum.value1, 1: nestedtest.MyEnum.value2}
In [9]: nestedtest.MyClass.MyEnum.value1
Out[9]: nestedtest.MyEnum.value1
In [10]: nestedtest.MyClass.MyEnum.value2
Out[10]: nestedtest.MyEnum.value2
(from my ipython shell, I tested this and all ;)
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