为什么我的命令行不能从cron运行？ [英] Why does my command-line not run from cron?

问题描述

我有一个perl脚本（ XMLTV 系列抓取者的一部分，特别是 tv_grab_oztivo ）。

I have a perl script (part of the XMLTV family of "grabbers", specifically tv_grab_oztivo).

我可以成功运行它：

/sw/bin/perl /path/to/tv_grab_oztivo --output /path/to/tv.xml

我使用完整的路径来消除工作目录中的问题。权限不应该是一个问题。

I use the full paths to everything to eliminate issues with the Working Directory. Permissions shouldn't be a problem.

所以，如果我从终端（Mac OSX）运行它，它的工作原理很好。

So, if I run it from the Terminal (Mac OSX) it works just fine.

但是当我将其设置为通过cron作业运行时，根本就不会发生任何事情。没有输出创建等。

But when I set it to run via a cron job, nothing appears to happen at all. No output is created etc.

尽管我看到crontab没有什么问题，因为如果我用一个helloworld.pl替代实际的脚本，它在正确的时间运行正常。

There isn't anything wrong with the crontab as far as I can see, because if I substitute a helloworld.pl for the actual script, it runs just fine at the right time.

那么我可以做什么来调试？在两种情况下，我们可以从％ENV 中看到，环境是非常不同的，但是我可以采取什么其他方法来调试？如何查看cron作业的输出，这可能是某种类型的死消息或从未找到的消息从shell或其他什么？

So, what can I do to debug? I can see from looking at %ENV in the two cases that the environment is very different, but what other approaches can I take to debugging? How can I see the output of the cron job, which might be some kind of perl "die" message or "not found" message from the shell or whatever?

或我应该尝试以某种方式给命令的cron版本与运行时一样的环境吗？

Or should I be trying to somehow give the cron version of the command the same environment as when it's running as me?

推荐答案

这是通常，因为在cron下运行时没有获得完整的环境。最好的办法是使用以下命令捕获输出：

It's often because you don't get the full environment when running under cron. Best bet is to capture the ouput by using the command:

( /sw/bin/perl /path/to/tv_grab_oztivo ... ) >/tmp/qq 2>&1

然后看看 / tmp / qq 。

如果它确实是缺少的环境，那么你可能需要放：

If it does turn out to be a missing environment, then you may need to put:

. ~/.profile

或类似的东西，进入你的cron作业的执行链，如： / p>

or something similar, into the execution chain of your cron job, such as:

( . ~/.profile ; /sw/bin/perl /path/to/tv_grab_oztivo ... ) >/tmp/qq 2>&1

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