JavaScript错误处理：我可以在三元运算符中抛出一个错误？ [英] JavaScript error handling: can I throw an error inside a ternary operator?

问题描述

我是否允许在三元运算符内发生错误？这是有效的：

  function foo（params）{
 
 var msg =（params.msg） ？ params.msg：（throwerror）; 
 
 //如果`params`内的所有内容定义为
} 
  

我想要做的是确保所有需要的参数，它们位于 param 对象中，并且会发生错误（如果有的话）没有定义

如果这只是愚蠢的，有没有更好的方法来做到这一点？

解决方案

您可以这样做：

  function foo（params）{
 
 var msg =（params.msg）？ params.msg：（function（）{throwerror}（））; 
 
 //如果`params`内的所有内容定义为
} 
  

我不会真的推荐它，它使得无法读取的代码。

这也可以工作（不是真的好多了）：

  function foo（params）{
 
 var msg = params.msg || （function（）{throwerror}（））; 
 
 //如果`params`内的所有内容定义为
} 
  

---

或者为了更清洁的方法，做一个命名的功能。

 函数_throw（m）{throw m; } 
  

  function foo params）{
 
 var msg = params.msg || _throw（ 错误）; 
 
 //如果params中的所有内容都被定义为
} 
  

Am I allowed to throw an error inside a ternary operator? Is this valid:

function foo(params) {

    var msg = (params.msg) ? params.msg : (throw "error");

    // do stuff if everything inside `params` is defined
}

What I'm trying to do is make sure all of the parameters needed, which are in a param object, are defined and throw an error if any one is not defined.

If this is just foolish, is there a better approach to doing this?

解决方案

You could do this:

function foo(params) {

    var msg = (params.msg) ? params.msg : (function(){throw "error"}());

    // do stuff if everything inside `params` is defined
}

I wouldn't really recommend it though, it makes for unreadable code.

This would also work (not that it's really much better):

function foo(params) {

    var msg = params.msg || (function(){throw "error"}());

    // do stuff if everything inside `params` is defined
}

---

Or for a cleaner approach, make a named function.

function _throw(m) { throw m; }

function foo(params) {

    var msg = params.msg || _throw("error");

    // do stuff if everything inside `params` is defined
}

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