将pugixml的result.offset转换为列/行 [英] Convert pugixml's result.offset to column/line
问题描述
我需要使用pugixml的应用程序的用户友好的错误报告。
我正在使用result.offset。
有没有办法获取行和列?
我可能处理大型XML文件,如果这有差异。
I need user-friendly error reporting for an application that uses pugixml.
I am currently using result.offset.
Is there a way to get the line and column instead?
I am potentially dealing with large XML files, if that makes a difference.
推荐答案
此功能不容易在pugixml中,因为在每个解析上执行相对昂贵,并且解析完成后,在一般情况下无法恢复文件/行信息。
This functionality is not readily available in pugixml since it's relatively expensive to do it on every parse, and after parsing is complete it's impossible to recover file/line information in the general case.
这是一个代码片段构建一个偏移 - >线映射,您可以在解析失败的情况下使用,或者由于其他原因需要信息;随时调整文件I / O代码以符合您的要求。
Here's a snippet that builds an offset -> line mapping that you can use in case parsing fails or you need the information for other reasons; feel free to tweak file I/O code to match your requirements.
typedef std::vector<ptrdiff_t> offset_data_t;
bool build_offset_data(offset_data_t& result, const char* file)
{
FILE* f = fopen(file, "rb");
if (!f) return false;
ptrdiff_t offset = 0;
char buffer[1024];
size_t size;
while ((size = fread(buffer, 1, sizeof(buffer), f)) > 0)
{
for (size_t i = 0; i < size; ++i)
if (buffer[i] == '\n')
result.push_back(offset + i);
offset += size;
}
fclose(f);
return true;
}
std::pair<int, int> get_location(const offset_data_t& data, ptrdiff_t offset)
{
offset_data_t::const_iterator it = std::lower_bound(data.begin(), data.end(), offset);
size_t index = it - data.begin();
return std::make_pair(1 + index, index == 0 ? offset + 1 : offset - data[index - 1]);
}
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