PHP：我应该如何逃避将要进入Javascript字符串的字符串？ [英] PHP: How should I escape a string that will be going into a Javascript String?

问题描述

我应该如何避免将要进入Javascript字符串的字符串？ URLEncode的（X）？ str_replace（'，\X）？

解决方案

使用 json_encode

所以你可以做

  $ page_params = array（
'user_logged_in'=> $ suer-> IsActive（），
'some_string'=>sajdhf\test''z\'\fsdf
'ts'=> time（）
）; 
 
 $ page_params = json_encode（$ page_params）; 
  

然后在你的模板中你可以去

  var page_params = ？php echo $ page_params？> ;; 
  

女巫会产生

  var page_params = {user_logged_in：false，some_string：sajdhf\test''z\'\\fsfs，ts 2452346543} 
  

这样可以将多个变量设置为1个字符串，并且转义由Json Library / p>

How should I escape a string that will be going into a Javascript String? URLEncode(X)? str_replace("'","\'",X)?

解决方案

use json_encode

so you can do

$page_params = array(
    'user_logged_in' => $suer->IsActive(),
    'some_string' => "sajdhf\"test''z\'\fsdf"
    'ts' => time()
);

$page_params = json_encode($page_params);

then in your template you can just go

var page_params = <?php echo $page_params ?>;

witch would produce

var page_params = {"user_logged_in":false,"some_string":"sajdhf\"test''z\'\fsdf","ts":2452346543}

this way you can set multiple variables to 1 string and escaping is done by the Json Library

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