通过Apache POI获取单元格参考信号标识符 [英] Get Cell by a Cell reference letter identifier with Apache POI

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本文介绍了通过Apache POI获取单元格参考信号标识符的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我试图通过单元格参考从行中获取单元格,并且我有一个问题。例如我有:

  row.getCell(CellReference.convertColStringToIndex(B)); 

如果列索引为 1 ,但是如果列被删除,因此 B 列索引变为 2 和方法: CellReference.convertColStringToIndex(B)仍然将其转换为 1 在这种情况下,我无法获取我的列,我得到 null



所以问题是如何从行中获取列取决于单元标识符是一个字母?

解决方案

看看我对上一个问题的回答: p>

您可能想使用 CellReference 实用工具类来帮助您。它提供Excel样式字母+数字引用和POI样式0基行+列之间的转换。使用它时,您可以执行以下操作:

  Sheet sheet = workbook.getSheet(MyInterestingSheet); 

CellReference ref = new CellReference(B12);
Row r = sheet.getRow(ref.getRow());
if(r!= null){
单元格c = r.getCell(ref.getCol());
}

这将让您在给定的Excel样式引用中找到单元格(if它被定义,否则为null)


I am trying to get the Cell from the Row by a Cell reference and I have a problem. For example I have:

row.getCell(CellReference.convertColStringToIndex("B"));

That works fine if the Column index is 1, but if Column was deleted so the B Column index became 2 and the method: CellReference.convertColStringToIndex("B") is still converting it to 1 in which case I can't get my Column, I am getting null.

So the question is how can I get the Column from the Row depending on Cell identifier which is a letter?

解决方案

Take a look at my answer to a previous question:

You probably want to use the CellReference utility class to help you out. It offers conversion between Excel style letter+number references, and POI style 0-based rows+columns. When using it, you can do something like:

 Sheet sheet = workbook.getSheet("MyInterestingSheet");

 CellReference ref = new CellReference("B12");
 Row r = sheet.getRow(ref.getRow());
 if (r != null) {
    Cell c = r.getCell(ref.getCol());
 }

That will let you find the cell at a given Excel-style reference (if it's defined, else null)

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