如何彻底扭转一个C风格的字符串 [英] How to reverse a C style string completely

问题描述

我想扭转一个C风格的字符串（空值终止）完全，即包括空字符。

I'd like to reverse a C style string (null-terminated) completely, i.e. including the null character.

空字符应当是在翻转串的第一个元素

The null character should be the first element in the reversed string.

推荐答案

这实际上是pretty的方便：

That's actually pretty easy:

char *reversed = "";

：）

C字符串开头的'\ 0'是一个空字符串。除非你做的不是字符串的东西（如添加+1），与预期的内存（指针+大小）的指针或使用的功能也不要紧什么来的'\ 0'

A C string starting with a '\0' is an empty string. And unless you do things (like adding +1) with the pointer or use functions which expect memory (pointer+size) instead of strings it doesn't matter what comes behind the '\0'

如果您真的需要真正的字符串，经过present在内存中的'\ 0'：以这写的逆转字符串给定的记忆功能位置（无效strreverse（字符* DEST，为const char *字符串））。 然后调用它像这样：字符DEST [ENOUGH_SPACE] DEST [0] ='\ 0'; strreverse（DEST + 1，YOUR_STRING）;

If you actually needed the real string to be present in memory after the '\0': Take the function which writes your reversed string to a given memory location (void strreverse(char *dest, const char *string)). Then call it like that: char dest[ENOUGH_SPACE]; dest[0] = '\0'; strreverse(dest + 1, YOUR_STRING);

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