python如何转换时间戳到"2017年6月12日 18点24分"这样的格式呢？

问题描述

问 题

python如何转换时间戳到"2017年6月12日 18点24分"这样的格式呢？谢谢

import time
timestamp = time.time()
time.strftime('%Y年%m月%d日 %H时%M分', time.localtime(timestamp))
Traceback (most recent call last):
  File "<input>", line 1, in <module>
UnicodeEncodeError: 'locale' codec can't encode character '\u5e74' in position 2: Illegal byte sequence

另外吐槽下，chrome下打开segmentfault显示内存用完崩溃的错误到底什么时候修啊啊啊啊啊啊！

解决方案

还真被我研究出来种万能方法，据我百度Google貌似这还是世上独一份？

话不多说，下面上解决原理及方案：

官方文档：https://docs.python.org/3/lib...

---

class time.`struct_time`¶

The type of the time value sequence returned by gmtime(), localtime(), and strptime(). It is an object with a named tuple interface: values can be accessed by index and by attribute name. The following values are present:

Index	Attribute	Values
0	tm_year	(for example, 1993)
1	tm_mon	range [1, 12]
2	tm_mday	range [1, 31]
3	tm_hour	range [0, 23]
4	tm_min	range [0, 59]
5	tm_sec	range [0, 61]; see (2) in strftime() description
6	tm_wday	range [0, 6], Monday is 0
7	tm_yday	range [1, 366]
8	tm_isdst	0, 1 or -1; see below
N/A	tm_zone	abbreviation of timezone name
N/A	tm_gmtoff	offset east of UTC in seconds

Note that unlike the C structure, the month value is a range of [1, 12], not [0, 11].
In calls to mktime(), tm_isdst may be set to 1 when daylight savings time is in effect, and 0 when it is not. A value of -1 indicates that this is not known, and will usually result in the correct state being filled in.
When a tuple with an incorrect length is passed to a function expecting a struct_time, or having elements of the wrong type, a TypeError is raised.

---

看文档可以得知time.localtime()返回的元组结构，我要用到的是年月日时分，前5个，于是乎，代码：

import time
print('%s年%s月%s日 %s时%s分' % time.localtime(1497254119.69407)[:5])

输出：

2017年6月12日 15时55分

搞定。

转载请注明出处，谢谢。

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