Android的 - android.os.NetworkOnMainThreadException [英] Android - android.os.NetworkOnMainThreadException

问题描述

我有这样的例外，我正在读这个线程，似乎令人困惑：

I have this exception and I was reading a thread on this, and it seemed confusing:

<一个href="http://stackoverflow.com/questions/6343166/android-os-networkonmainthreadexception">android.os.NetworkOnMainThreadException

我已经添加了此行到我的清单：

I already added this line to my manifest:

<uses-permission android:name="android.permission.INTERNET" />

在这次讨论，他们谈论的应用程序不能够做到网络的主执行线程。我想知道的是如何调整我的code，使其内嵌Android的良好做法。

On that discussion, they talk about the main execution thread of the app not being able to do networking. What I am wondering is how to restructure my code so that it is inline with Android good practices.

下面是我的活动类的：

package com.problemio;

import java.io.InputStream;
import java.util.ArrayList;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;

import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
public class LoginActivity extends Activity 
{
    public void onCreate(Bundle savedInstanceState) 
    {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.login);

        // Show form for login_email
        final EditText loginEmail = (EditText) findViewById(R.id.login_email);  
        String name = loginEmail.getText().toString();  

        // Show field for password  
        final EditText password = (EditText) findViewById(R.id.password);  
        String text = password.getText().toString();                  

        // Show button for submit
        Button submit = (Button)findViewById(R.id.submit);   




        // Show options for create-profile and forgot-password




        submit.setOnClickListener(new Button.OnClickListener() 
        {  
           public void onClick(View v) 
           {
              String email = loginEmail.getText().toString();
              String pass = password.getText().toString(); 
              sendFeedback(pass, email);
            }
        });        
    }


    public void sendFeedback(String pass , String email) 
    {  
        Log.d( "1" , pass );
        Log.d( "1" , email );

        // Go to db and check if these r legit
        // How do I do that? :)
        ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>();  
        postParameters.add(new BasicNameValuePair("username", email ));  
        postParameters.add(new BasicNameValuePair("password", pass ));

        String responseString = null;

        try 
        {  
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost("myUrl");

            // no idea what this does :)
            httppost.setEntity(new UrlEncodedFormEntity(postParameters));

            // This is the line that send the request
            HttpResponse response = httpclient.execute(httppost);

            HttpEntity entity = response.getEntity();            

            InputStream is = entity.getContent();
        } 
        catch (Exception e) 
        {     
            Log.e("log_tag", "Error in http connection "+e.toString());
        }        
    }          
}

我在做什么错在这里，我怎么能解决这个问题？ :)谢谢！

What am I doing wrong here and how could I fix it? :) Thanks!!

推荐答案

NetworkOnMainThreadException：当应用程序试图在其主线程进行网络操作时引发的异常

NetworkOnMainThreadException: The exception that is thrown when an application attempts to perform a networking operation on its main thread.

您应该调用sendfeedback方法上的AsyncTask则仅高于code会工作。由于Web服务器正在采取大量的时间来响应主线程变得反应迟钝。为了避免它，你应该把它在另一个线程。因此AsyncTask的比较好。

You should call sendfeedback method on asynctask then only above code will work. As webserver is taking lot of time to response main thread becomes unresponsive. To avoid it you should call it on another thread. Hence asynctask is better.

下面是说明如何使用AsyncTask的链接

here is link that illustrates how to use asynctask

这篇关于Android的 - android.os.NetworkOnMainThreadException的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！